bash – 在shell脚本中使用if elif fi

发布时间：2020-12-15 19:02:58 所属栏目：安全来源：网络整理

导读：参见英文答案 Simple logical operators in Bash5个我不确定如何在shell中进行多次测试.我在编写这个脚本时遇到了麻烦： echo "You have provided the following arguments $arg1 $arg2 $arg3"if [ "$arg1" = "$arg2" "$arg1" != "$arg3" ]then echo "Two o

参见英文答案 > Simple logical operators in Bash5个
我不确定如何在shell中进行多次测试.我在编写这个脚本时遇到了麻烦：

echo "You have provided the following arguments $arg1 $arg2 $arg3"
if [ "$arg1" = "$arg2" && "$arg1" != "$arg3" ]
then
    echo "Two of the provided args are equal."
    exit 3
elif [ $arg1 = $arg2 && $arg1 = $arg3 ]
then
    echo "All of the specified args are equal"
    exit 0
else
    echo "All of the specified args are different"
    exit 4
fi

问题是我每次都会收到此错误：

./compare.sh: [: missing `]’ command not found

sh正在解释&&作为shell运算符.将它更改为-a,这是[的连接操作符：

[ "$arg1" = "$arg2" -a "$arg1" != "$arg3" ]

此外,你应该总是引用变量,因为[当你放弃参数时会感到困惑.

（编辑：李大同）

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