如何在bash中显示和刷新多行
发布时间:2020-12-15 18:59:05 所属栏目:安全 来源:网络整理
导读:我正在编写安装脚本,并希望在脚本进行过程中显示脚本的状态. 例: var1="pending"var2="pending"var3="pending"print_status () {echo "Status of Item 1 is: "$var1""echo "Status of Item 2 is: "$var2""echo "Status of Item 3 is: "$var3""}code that do
我正在编写安装脚本,并希望在脚本进行过程中显示脚本的状态.
例: var1="pending" var2="pending" var3="pending" print_status () { echo "Status of Item 1 is: "$var1"" echo "Status of Item 2 is: "$var2"" echo "Status of Item 3 is: "$var3"" } code that does something and then refreshes the output above as the status of each variable changes.
这段代码应该给你一个想法:
while :; do echo "$RANDOM" echo "$RANDOM" echo "$RANDOM" sleep 0.2 tput cuu1 # move cursor up by one line tput el # clear the line tput cuu1 tput el tput cuu1 tput el done 使用man tput获取更多信息.要查看功能列表,请使用man terminfo (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |