shell – “set -e”在一个函数中

如何在函数中获得相当于此的内容？

例如,我有以下脚本立即退出错误退出状态：

#!/bin/sh -e

echo "the following command could fail:"
false
echo "this is after the command that fails"

产出如预期的那样：

the following command could fail:

现在我想把它包装成一个函数：

#!/bin/sh -e

my_function() {
    echo "the following command could fail:"
    false
    echo "this is after the command that fails"
}

if ! my_function; then
    echo "dealing with the problem"
fi

echo "run this all the time regardless of the success of my_function"

预期产量：

the following command could fail:
dealing with the problem
run this all the time regardless of the success of my_function

实际输出：

the following output could fail:
this is after the command that fails
run this all the time regardless of the success of my_function

(即函数忽略set -e)

这可能是预期的行为.我的问题是：如何在shell函数中获得set -e的效果和有用性？我发现the same question在Stack Overflow外面询问,但没有合适的答案.