bash – 具有相同名称的本地只读与全局只读变量的函数
发布时间:2020-12-15 18:36:58 所属栏目:安全 来源:网络整理
导读:当我有一个函数本地只读变量和具有相同名称的全局只读变量时,我会得到一个惊人的行为. 当从全局声明中删除只读选项时.即 declare -r var="main" 改为: declare var="main" 我得到了预期的行为.我一直在阅读bash手册页,但我找不到这个行为的解释.你能请我指
当我有一个函数本地只读变量和具有相同名称的全局只读变量时,我会得到一个惊人的行为.
当从全局声明中删除只读选项时.即 declare -r var="main" 改为: declare var="main" 我得到了预期的行为.我一直在阅读bash手册页,但我找不到这个行为的解释.你能请我指出手册中解释这个问题的部分吗? 我认为这是一个类似的问题,比How does lexical scoping supported in different shell languages?更具体. 细节: $cat readonly_variable.sh #!/bin/bash # expected output: # # BASH_VERSION = 3.2.25(1)-release # function # main # # but instead getting: # # BASH_VERSION = 3.2.25(1)-release # ./readonly_variable.sh: line 6: local: var: readonly variable # main # main # # when read-only option (-r) is removed from global declaration (*),the output # is expected set -o nounset function func { local -r var="function" echo "$var" } declare -r var="main" # (*) echo BASH_VERSION = $BASH_VERSION echo $(func) echo $var exit 0 我陷入了这个特殊的Bash版本. $./readonly_variable.sh BASH_VERSION = 3.2.25(1)-release ./readonly_variable.sh: line 24: local: var: readonly variable main main $
实际上,为了安全起见,明确地禁止只读全局变量的本地副本,如bash源代码(在variables.c:make_local_variable中)所示:
(其中“我”不是我,我只是引用) /* Since this is called only from the local/declare/typeset code,we can call builtin_error here without worry (of course,it will also work for anything that sets this_command_name). Variables with the `noassign' attribute may not be made local. The test against old_var's context level is to disallow local copies of readonly global variables (since I believe that this could be a security hole). Readonly copies of calling function local variables are OK. */ if (old_var && (noassign_p (old_var) || (readonly_p (old_var) && old_var->context == 0))) { if (readonly_p (old_var)) sh_readonly (name); return ((SHELL_VAR *)NULL); } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |