在.vimrc中运行shell脚本(并处理输出)

发布时间：2020-12-15 17:00:38 所属栏目：安全来源：网络整理

导读：我试图从. vimrc文件中运行一个 shell脚本(脚本中标记了三个问题)： function! CheckMe(file) let shellcmd = 'checkme '.a:file " Start the command and return 0 on success. " XXX: How do you evaluate the return code? execute '!'.shellcmd if !resu

我试图从. vimrc文件中运行一个 shell脚本(脚本中标记了三个问题)：

function! CheckMe(file)
    let shellcmd = 'checkme '.a:file

    " Start the command and return 0 on success.
    " XXX: How do you evaluate the return code?
    execute '!'.shellcmd
    if !result
        return 0
    endif

    " Ending up here,the command returned an error.
    " XXX: Where to you get the output?
    let pair = split(output,'S')
    let line = pair[0]
    let char = pair[1]

    " Jump to the errenous column and line.
    " XXX: Why does this not work?
    normal '/%'.line.'l%'.char.'c'
    return 1
endfunction

总而言之,如何获得脚本的结果/输出,以及为什么跳转语句不起作用？

额外细节：

> shell脚本在成功时返回0,在失败时返回1.如果失败,脚本会将两个数字(行号和列号)打印到stdout,用空格字符分隔.
>根据Vim docs,“普通”关键字的参数是“像打字一样执行”,但显然情况并非如此.当我输入它时(在正常命令模式下,没有前导’：’)它工作正常,但在脚本中没有(“E78：未知标记”).

function! CheckMe(file)
    let shellcmd = 'checkme '.a:file

    let output=system(shellcmd)
    if !v:shell_error
        return 0
    endif

    " Are you sure you want to split on non-blanks? This 
    " will result in list of blank strings.
    " My variant:
    let [line,char]=split(output)

    " Normal is not an execute: this is what it will do:
    " ?'/? means ?Go to mark /?,produces an error E78 because /
    " is not a valid symbol for mark. Than normal stops after error occured.
    " If you need to use variables in nomal use ?execute 'normal '.ncmd?.
    " And you can not use ?normal? to perform search
    execute '/%'.line.'l%'.char.'c'
    " or
    call setpos('.',[0,line,char,0])
    return 1
endfunction

According to the Vim docs,the argument of the “normal” keyword is “executed like it is typed”,but apparently that is not the case. It works fine when I type it (in the normal command mode,without leading ‘:’),but doesn’t in the script (“E78: Unknown mark).

只需输入?’/?即可得到此错误.

（编辑：李大同）

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