如何在bash中使用mod运算符?
发布时间:2020-12-15 16:47:30 所属栏目:安全 来源:网络整理
导读:我试着这样一行: for i in {1..600}; do wget http://mydomain.com/search/link $i % 5; done; 我想得到的输出是: wget http://mydomain.com/search/link0wget http://mydomain.com/search/link1wget http://mydomain.com/search/link2wget http://mydomai
我试着这样一行:
for i in {1..600}; do wget http://mydomain.com/search/link $i % 5; done; 我想得到的输出是: wget http://mydomain.com/search/link0 wget http://mydomain.com/search/link1 wget http://mydomain.com/search/link2 wget http://mydomain.com/search/link3 wget http://mydomain.com/search/link4 wget http://mydomain.com/search/link0 但我实际得到的只是: wget http://mydomain.com/search/link
尝试以下操作:
for i in {1..600}; do echo wget http://mydomain.com/search/link$(($i % 5)); done $(())语法做一个arithmetic evaluation的内容。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |