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shell脚本中位置参数 $0 $1 .. $* $#的备忘

发布时间:2020-12-15 07:12:38 所属栏目:安全 来源:网络整理
导读:今天PHP站长网 52php.cn把收集自互联网的代码分享给大家,仅供参考。 #!/bin/bashMIN_PARAMS=10echoecho "The name of this script is "`basename $0`"."echoif [ -n "$1" ]; then echo "param #1 is $1"fiif [ -n "$2"

以下代码由PHP站长网 52php.cn收集自互联网

现在PHP站长网小编把它分享给大家,仅供参考

#!/bin/bash
MIN_PARAMS=10
echo
echo "The name of this script is "`basename $0`"."

echo
if [ -n "$1" ]; then
 echo "param #1 is $1"
fi
if [ -n "$2" ]; then
  echo "param #2 is $2"
fi
if [ -n "$3" ]; then
  echo "param #3 is $3"
fi
echo "______________________________"
echo "All command-line params are : $*"
echo '$0 =' "$0"
echo '$# =' "$#"
echo '[email?protected] =' "[email?protected]"
echo '$* =' "$*"
if [ $# -lt $MIN_PARAMS ]
then 
   echo
   echo "this script need at least $MIN_PARAMS"
fi
exit 0
________________________________________________________
执行 $ /tmp/ts.sh 1 2 3 4 5 6
打印出来的结果

The name of this script is "ts.sh".

param #1 is 1
param #2 is 2
param #3 is 3
______________________________
All command-line params are : 1 2 3 4 5 6
$0 = /tmp/ts.sh
$# = 6
[email?protected] = 1 2 3 4 5 6
$* = 1 2 3 4 5 6
this script need at least 10

以上内容由PHP站长网【52php.cn】收集整理供大家参考研究

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