Windows Qt以及如何在没有OpenCV的情况下捕获网络摄像头

我使用了一个名为“ESCAPI”的库：http://sol.gfxile.net/escapi/index.html

这提供了一种从设备捕获帧的极其简单的方法.使用这些原始数据,我只需创建一个QImage,稍后将在QLabel中显示.

我创建了一个简单的对象来处理它.

#include <QDebug>
#include "camera.h"

Camera::Camera(int width,int height,QObject *parent) :
    QObject(parent),width_(width),height_(height)
{
    capture_.mWidth = width;
    capture_.mHeight = height;
    capture_.mTargetBuf = new int[width * height];

    int devices = setupESCAPI();
    if (devices == 0)
    {
        qDebug() << "[Camera] ESCAPI initialization failure or no devices found";
    }
}

Camera::~Camera()
{
    deinitCapture(0);
}

int Camera::initialize()
{
    if (initCapture(0,&capture_) == 0)
    {
        qDebug() << "[Camera] Capture failed - device may already be in use";
        return -2;
    }
    return 0;
}

void Camera::deinitialize()
{
    deinitCapture(0);
}

int Camera::capture()
{
    doCapture(0);
    while(isCaptureDone(0) == 0);

    image_ = QImage(width_,height_,QImage::Format_ARGB32);
    for(int y(0); y < height_; ++y)
    {
        for(int x(0); x < width_; ++x)
        {
            int index(y * width_ + x);
            image_.setPixel(x,y,capture_.mTargetBuf[index]);
         }
    }
    return 1;
}

和头文件：

#ifndef CAMERA_H
#define CAMERA_H

#include <QObject>
#include <QImage>
#include "escapi.h"

class Camera : public QObject
{
    Q_OBJECT

public:
    explicit Camera(int width,QObject *parent = 0);
    ~Camera();
    int initialize();
    void deinitialize();
    int capture();
    const QImage& getImage() const { return image_; }
    const int* getImageRaw() const { return capture_.mTargetBuf; }

private:
    int width_;
    int height_;
    struct SimpleCapParams capture_;
    QImage image_;
};

#endif // CAMERA_H

这很简单,但仅仅是出于示例目的.
使用应该是这样的：

Camera cam(320,240);
cam.initialize();
cam.capture();
QImage img(cam.getImage());
ui->label->setPixmap(QPixmap::fromImage(img));

当然,您可以使用QTimer并在QLabel中更新框架,您将在那里看到视频……

希望它有所帮助！并感谢尼古拉斯的帮助！