windows-8 – 在Windows 8应用程序中保存List的最佳方法是什么

StorageFolder folder = ApplicationData.Current.LocalFolder;

然后使用以下参考文件保存在那里：

var fileToGet = await folder.GetFileAsync("nameOfFile.fileType");

我目前处于我正在处理的项目中的类似情况,我希望将自定义对象列表存储到我的Apps LocalFolder并稍后重新加载.

我的解决方案是将列表序列化为XML字符串,并将其存储在App文件夹中.你应该能够调整我的方法：

static public string SerializeListToXml(List<CustomObject> List)
    {
        try
        {
            XmlSerializer xmlIzer = new XmlSerializer(typeof(List<CustomObject>));
            var writer = new StringWriter();
            xmlIzer.Serialize(writer,List);
            System.Diagnostics.Debug.WriteLine(writer.ToString());
            return writer.ToString();
        }

        catch (Exception exc)
        {
            System.Diagnostics.Debug.WriteLine(exc);
            return String.Empty;
        }

现在您已经拥有了该字符串,您可以将其保存为文本文件并将其放在LocalStorage中：

//assuming you already have a list with data called myList
await Windows.Storage.FileIO.WriteTextAsync("xmlFile.txt",SerializeListToXml(myList));

现在,当您再次加载应用程序时,您可以使用上面提到的加载方法从LocalStorage获取xmlFile,然后对其进行反序列化以使List返回.

string listAsXml = await Windows.Storage.FileIO.ReadTextAsync(xmlFile.txt);
List<CustomObject> deserializedList = DeserializeXmlToList(listAsXml);

再次,根据您的需求进行调整：

public static List<CustomObject> DeserializeXmlToList(string listAsXml)
    {
        try
        {
            XmlSerializer xmlIzer = new XmlSerializer(typeof(List<CustomObject>));
            XmlReader xmlRead = XmlReader.Create(listAsXml);
            List<CustomObject> myList = new List<CustomObject>();
            myList = (xmlIzer.Deserialize(xmlRead)) as List<CustomObject>;
            return myList;
        }

        catch (Exception exc)
        {
            System.Diagnostics.Debug.WriteLine(exc);
            List<CustomObject> emptyList = new List<CustomObject>();
            return emptyList;
        }
    }