linux – 没有NSURLRequest的Swift中的HTTP请求

这是一个代码示例：

import HTTP
import HTTPMiddleware

struct Middleware: HTTPRequestMiddlewareType {
    func respond(request: HTTPRequest) -> HTTPRequestMiddlewareResult {
        // You can change the request and pass it forward
        return .Next(request)

        // Or you can respond early and bypass the chain
        return .Respond(HTTPResponse(statusCode: 404,reasonPhrase: "Not Found"))
    }
}

struct Responder: HTTPResponderType {
    func respond(request: HTTPRequest) -> HTTPResponse {
        // May or may not be called depending on the middleware
        return HTTPResponse(statusCode: 200,reasonPhrase: "OK")
    }
}

let request = HTTPRequest(method: .GET,uri: URI(path: "/"))
let chain = Middleware() >>> Responder()
let response = chain.respond(request)

这是官方的page,你也可以在源代码中找到一个对常见请求有用的JSON解析器.安装只需要uri_parser.