Linux:删除不包含特定行数的文件
发布时间:2020-12-14 01:52:00 所属栏目:Linux 来源:网络整理
导读:如何删除目录中具有多于或少于指定行数的文件(所有文件都有“.txt”后缀)? 解决方法 这个bash脚本应该可以解决问题.保存为“rmlc.sh”. 样品用法: rmlc.sh -more 20 *.txt # Remove all .txt files with more than 20 linesrmlc.sh -less 15 * # Remove AL
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如何删除目录中具有多于或少于指定行数的文件(所有文件都有“.txt”后缀)?
解决方法
这个bash脚本应该可以解决问题.保存为“rmlc.sh”.
样品用法: rmlc.sh -more 20 *.txt # Remove all .txt files with more than 20 lines rmlc.sh -less 15 * # Remove ALL files with fewer than 15 lines 请注意,如果rmlc.sh脚本位于当前目录中,则会对其进行保护以防删除. #!/bin/sh
# rmlc.sh - Remove by line count
SCRIPTNAME="rmlc.sh"
IFS=""
# Parse arguments
if [ $# -lt 3 ]; then
echo "Usage:"
echo "$SCRIPTNAME [-more|-less] [numlines] file1 file2..."
exit
fi
if [ $1 == "-more" ]; then
COMPARE="-gt"
elif [ $1 == "-less" ]; then
COMPARE="-lt"
else
echo "First argument must be -more or -less"
exit
fi
LINECOUNT=$2
# Discard non-filename arguments
shift 2
for filename in $*; do
# Make sure we're dealing with a regular file first
if [ ! -f "$filename" ]; then
echo "Ignoring $filename"
continue
fi
# We probably don't want to delete ourselves if script is in current dir
if [ "$filename" == "$SCRIPTNAME" ]; then
continue
fi
# Feed wc with stdin so that output doesn't include filename
lines=`cat "$filename" | wc -l`
# Check criteria and delete
if [ $lines $COMPARE $LINECOUNT ]; then
echo "Deleting $filename"
rm "$filename"
fi
done
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