linux – Winsock2如何监听()阻止？

sockaddr_in addr    = {0};
int     addrlen = sizeof(addr);
SOCKET  sock_listen;

if(-1 == (sock_listen = socket(AF_INET,SOCK_STREAM,IPPROTO_TCP)))
{
    cout<<"error";
}   

addr.sin_family = AF_INET;
/* Network byte ordered address for loopback */
addr.sin_addr.s_addr= inet_addr("127.0.0.1");
/* Let service provider assign a unique port from dynamic client port range */  
addr.sin_port   = 0;                        

if(-1 == bind(sock_listen,(const sockaddr *)&addr,addrlen))       
{
    CloseHandle((HANDLE)sock_listen_fd);
    cout<<"error";
}

if(-1 == getsockname(sock_listen,(sockaddr *)&addr,&addrlen))
{     
    CloseHandle((HANDLE)sock_listen);
    cout<<"error";
}

u_long mode = 0;
if(SOCKET_ERROR == ioctlsocket(sock_listen,FIONBIO,&mode))
{
    cout<<"ioctl failed";
}

if(SOCKET_ERROR == listen(sock_listen,1))
{
    cout<<"listen error";
}
cout<<"Passed listen";
if(SOCKET_ERROR == (s = ACL_accept(sock_listen_fd,NULL,NULL)))
{
       cout<<"accept error";
}

默认情况下,创建为阻塞类型的套接字句柄.为了进一步确保它调用ioctlsocket()来使套接字句柄阻塞类型.

The output is : Passed listen

所以,线程在listen()时没有阻塞,而是根据我的知识阻止接受,这是正确的方式.同样在Linux MAN page,它清楚地解释了：

listen() marks the socket referred to by socket fd as a passive socket,i.e,as a socket that will be used to accept incoming connection requests using accept()

那么为什么MSDN说listen是一个阻塞的Winsock调用.他们只是意味着任何内部等待某事件？