需要将命令行(Linux)CURL转换为带有请求数据有效负载(“-d”)的P

发布时间：2020-12-13 13:51:09 所属栏目：Linux 来源：网络整理

导读：这是命令行CURL代码： curl -X POST "http://{$HOST}/api/1/videos.json" -H "Content-type: application/json" -H "X-Reseller-Email: $RESELLER" -H "X-Reseller-Token: $TOKEN" -H "X-User-Email: $USER" -d '{"video":{ "title": "My video from AP

这是命令行CURL代码： –

curl -X POST "http://{$HOST}/api/1/videos.json" 
-H "Content-type: application/json" 
-H "X-Reseller-Email: $RESELLER" 
-H "X-Reseller-Token: $TOKEN" 
-H "X-User-Email: $USER" 
-d '{"video":{
        "title": "My video from API","description": "Description from API","video_template_id": "16","track_id": "26","texts": [ 
            { 
                "layer": "VLN_txt_01","value": "My text 1"
            } 
        ],"images": [ 
            { 
                "layer": "VLN_icon_01","source": "icon","icon_id": "1593"
            } 
        ] 
    }}'

请帮我转换成PHP CURL调用.此外,我需要使用POST和PUT方法进行此调用.我已经创建了但是无法在PHP中转换数据有效负载.

我只需要知道如何在PHP中编写“-d”(数据),这与PHP中的命令行CURL调用相同.

最佳答案

您必须将CURLOPT_POSTFIELDS选项与CURLOPT_HTTPHEADER结合使用. CURLOPT_POSTFIELDS选项必须设置为JSON字符串,CURLOPT_HTTPHEADER – 包含所有需要的HTTP标头(包括Content-type)的数组.

所以代码应如下所示：

$json = '{"video":{
        "title": "My video from API","icon_id": "1593"
            } 
        ] 
    }}';

$ch = curl_init();
curl_setopt_array($ch,array(
    CURLOPT_URL => "http://{$HOST}/api/1/videos.json",CURLOPT_NOBODY => false,CURLOPT_RETURNTRANSFER => true,CURLOPT_POST => true,CURLOPT_POSTFIELDS => $json,CURLOPT_HTTPHEADER => array(
        "Content-type: application/json","X-Reseller-Email: $RESELLER","X-Reseller-Token: $TOKEN","X-User-Email: $USER",),));
$response = curl_exec($ch);
if ($response && curl_getinfo($ch,CURLINFO_HTTP_CODE) == 200)
    echo $response;

（编辑：李大同）

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