1110 Complete Binary Tree (25 分)
Given a tree,you are supposed to tell if it is a complete binary tree. Input Specification:Each input file contains one test case. For each case,the first line gives a positive integer?N?(≤) which is the total number of nodes in the tree -- and hence the nodes are numbered from 0 to?N?1. Then?N?lines follow,each corresponds to a node,and gives the indices of the left and right children of the node. If the child does not exist,a? Output Specification:For each case,print in one line? Sample Input 1:9 7 8 - - - - - - 0 1 2 3 4 5 - - - - Sample Output 1:YES 8 Sample Input 2:8 - - 4 5 0 6 - - 2 3 - 7 - - - - Sample Output 2:
/* 思路是先建树,找根节点,先序遍历找到最大节点,如果等于n表示完全二叉树 */ #include<iostream> #include<cstdlib> using namespace std; const int maxn = 21; bool isRoot[maxn] = {0}; int max_index = -1,last_v; int root = 0; struct Node { int left,right; }node[maxn]; int getNum(string s) { int iRet = -1; if(s != "-") { iRet = atoi(s.c_str()); isRoot[iRet] = 1; } return iRet; } void FindRoot(int n) { for(int i = 0; i < n; i++) { if(0 == isRoot[i]) { root = i; break; } } } void preOrder(int v,int index) { if(-1 == v) { return; } if(index > max_index) { max_index = index; last_v = v; } preOrder(node[v].left,index*2); preOrder(node[v].right,index*2+1); } int main() { int n; cin >> n; string s1,s2; for(int i = 0; i < n; i++) { cin >> s1 >> s2; node[i].left = getNum(s1); node[i].right = getNum(s2); } FindRoot(n); preOrder(root,1); if(max_index == n) { printf("YES %d",last_v); } else { printf("NO %d",root); } return 0; } 下面版本三个点段错误,待查 #include<cstdio> const int maxn = 30; struct Node { int left,right; }node[maxn]; int max_index = -1,last_v; bool isRoot[maxn] = {0}; int root; int changeNum(char c) { int iRet = -1; if(c != ‘-‘) { iRet = c - ‘0‘; isRoot[iRet] = 1; } return iRet; } void FindRoot(int n) { for(int i = 0; i < n; i++) { if(0 == isRoot[i]) { root = i; break; } } } void preOrder(int v,index*2+1); } int main() { int n; scanf("%d",&n); char c1,c2; for(int i = 0; i < n; i++) { getchar(); scanf("%c%*c%c",&c1,&c2); node[i].left = changeNum(c1); node[i].right = changeNum(c2); } FindRoot(n); preOrder(root,root); } return 0; } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |