linux – 什么原因和如何避免[FIN,ACK],[RST]和[RST,ACK]

发布时间：2020-12-13 19:29:34 所属栏目：Linux 来源：网络整理

导读：什么原因和如何避免[FIN,ACK],[RST]和[RST,ACK]？是由于SO的TCP参数之间的一些不匹配吗？当服务器在TCP / IP连接中回复[FIN,ACK]时,这意味着什么？ 10.118.113.237是一个Solaris框,而10.118.110.63是一个Linux框. No. Time Source Destination Protocol Len

什么原因和如何避免[FIN,ACK],[RST]和[RST,ACK]？

是由于SO的TCP参数之间的一些不匹配吗？当服务器在TCP / IP连接中回复[FIN,ACK]时,这意味着什么？

10.118.113.237是一个Solaris框,而10.118.110.63是一个Linux框.

No.     Time           Source                Destination           Protocol Length Info
  1 0.000000000    10.118.113.237        10.118.110.63         TCP      68     mmpft > 39679 [FIN,ACK] Seq=1 Ack=1 Win=49232 Len=0 TSval=62389927 TSecr=355193509
  2 0.000015000    10.118.110.63         10.118.113.237        TCP      56     39679 > mmpft [RST] Seq=1 Win=0 Len=0
  4 0.119357000    10.118.110.63         10.118.113.237        TCP      68     39707 > mmpft [ACK] Seq=1 Ack=93 Win=54 Len=0 TSval=355208473 TSecr=62389939
  5 0.119475000    10.118.113.237        10.118.110.63         TCP      62     mmpft > 39707 [RST,ACK] Seq=93 Ack=1 Win=0 Len=0
  6 0.321336000    10.118.110.63         10.118.113.237        TCP      76     55603 > mmpft [SYN] Seq=0 Win=5840 Len=0 MSS=1460 SACK_PERM=1 TSval=355208524 TSecr=0 WS=128
  7 0.321835000    10.118.113.237        10.118.110.63         TCP      80     mmpft > 55603 [SYN,ACK] Seq=0 Ack=1 Win=49232 Len=0 TSval=62389959 TSecr=355208524 MSS=1460 WS=1 SACK_PERM=1
  8 0.321854000    10.118.110.63         10.118.113.237        TCP      68     55603 > mmpft [ACK] Seq=1 Ack=1 Win=5888 Len=0 TSval=355208524 TSecr=62389959
  9 0.322552000    10.118.110.63         10.118.113.237        DIAMETER 276    cmd=Capabilities-ExchangeRequest(257) flags=R--- appl=Diameter Common Messages(0) h2h=3f3197c e2e=e9200846
 10 0.322891000    10.118.113.237        10.118.110.63         TCP      68     mmpft > 55603 [ACK] Seq=1 Ack=209 Win=49024 Len=0 TSval=62389959 TSecr=355208524
 11 0.342554000    10.118.113.237        10.118.110.63         TCP      68     mmpft > 39707 [FIN,ACK] Seq=93 Ack=1 Win=49232 Len=0 TSval=62389961 TSecr=355200968
 12 0.342567000    10.118.110.63         10.118.113.237        TCP      56     39707 > mmpft [RST] Seq=1 Win=0 Len=0
 13 0.346940000    10.118.113.237        10.118.110.63         DIAMETER 312    cmd=Capabilities-ExchangeAnswer(257) flags=---- appl=Diameter Common Messages(0) h2h=3f3197c e2e=e9200846
 14 0.347021000    10.118.110.63         10.118.113.237        TCP      68     55603 > mmpft [ACK] Seq=209 Ack=245 Win=6912 Len=0 TSval=355208530 TSecr=62389961
 15 4.288733000    10.118.113.237        10.118.110.63         TCP      68     mmpft > 39652 [FIN,ACK] Seq=1 Ack=1 Win=49232 Len=0 TSval=62390356 TSecr=355186382
 16 4.288757000    10.118.110.63         10.118.113.237        TCP      56     39652 > mmpft [RST] Seq=1 Win=0 Len=0
 17 4.398722000    10.118.113.237        10.118.110.63         DIAMETER 160    [TCP Retransmission] cmd=Device-WatchdogRequest(280) flags=R--- appl=Diameter Common Messages(0) h2h=f889ad2 e2e=5f8035e4
 18 4.398734000    10.118.110.63         10.118.113.237        TCP      56     39707 > mmpft [RST] Seq=1 Win=0 Len=0
 19 4.938748000    10.118.113.237        10.118.110.63         DIAMETER 160    cmd=Device-WatchdogRequest(280) flags=R--- appl=Diameter Common Messages(0) h2h=f889ad0 e2e=5f8035df
 20 4.938770000    10.118.110.63         10.118.113.237        TCP      56     39598 > mmpft [RST] Seq=1 Win=0 Len=0
 21 5.498759000    10.118.113.237        10.118.110.63         TCP      68     mmpft > 39544 [FIN,ACK] Seq=1 Ack=1 Win=49232 Len=0 TSval=62390477 TSecr=355156526
 22 5.498783000    10.118.110.63         10.118.113.237        TCP      56     39544 > mmpft [RST] Seq=1 Win=0 Len=0
 23 5.648780000    10.118.113.237        10.118.110.63         TCP      68     mmpft > 55774 [FIN,ACK] Seq=1 Ack=1 Win=49232 Len=0 TSval=62390492 TSecr=355111580
 24 5.648804000    10.118.110.63         10.118.113.237        TCP      56     55774 > mmpft [RST] Seq=1 Win=0 Len=0
 25 5.942885000    10.118.113.237        10.118.110.63         TCP      68     mmpft > 55828 [FIN,ACK] Seq=1 Ack=1 Win=49232 Len=0 TSval=62390521 TSecr=355126129
 26 5.942901000    10.118.110.63         10.118.113.237        TCP      56     55828 > mmpft [RST] Seq=1 Win=0 Len=0
 27 6.668742000    10.118.113.237        10.118.110.63         TCP      68     mmpft > 55666 [FIN,ACK] Seq=1 Ack=1 Win=49232 Len=0 TSval=62390594 TSecr=355081310
 28 6.668760000    10.118.110.63         10.118.113.237        TCP      56     55666 > mmpft [RST] Seq=1 Win=0 Len=0
 29 7.258815000    10.118.113.237        10.118.110.63         TCP      68     mmpft > 55720 [FIN,ACK] Seq=1 Ack=1 Win=49232 Len=0 TSval=62390653 TSecr=355096418
 31 7.418827000    10.118.113.237        10.118.110.63         DIAMETER 160    cmd=Device-WatchdogRequest(280) flags=R--- appl=Diameter Common Messages(0) h2h=f889acd e2e=5f8035d9
 32 7.418835000    10.118.110.63         10.118.113.237        TCP      56     39490 > mmpft [RST] Seq=1 Win=0 Len=0
 33 12.948752000   10.118.113.237        10.118.110.63         DIAMETER 160    [TCP Retransmission] cmd=Device-WatchdogRequest(280) flags=R--- appl=Diameter Common Messages(0) h2h=f889ad2 e2e=5f8035e4
 34 12.948776000   10.118.110.63         10.118.113.237        TCP      56     39707 > mmpft [RST] Seq=1 Win=0 Len=0
 35 30.030087000   10.118.113.237        10.118.110.63         DIAMETER 160    [TCP Retransmission] cmd=Device-WatchdogRequest(280) flags=R--- appl=Diameter Common Messages(0) h2h=f889ad2 e2e=5f8035e4
 36 30.030113000   10.118.110.63         10.118.113.237        TCP      56     39707 > mmpft [RST] Seq=1 Win=0 Len=0
 38 30.369302000   10.118.110.63         10.118.113.237        TCP      68     55603 > mmpft [ACK] Seq=209 Ack=337 Win=6912 Len=0 TSval=355216035 TSecr=62392964
 39 30.369413000   10.118.113.237        10.118.110.63         TCP      62     mmpft > 55603 [RST,ACK] Seq=337 Ack=209 Win=0 Len=0
 40 30.571231000   10.118.110.63         10.118.113.237        TCP      76     55630 > mmpft [SYN] Seq=0 Win=5840 Len=0 MSS=1460 SACK_PERM=1 TSval=355216086 TSecr=0 WS=128
 41 30.571603000   10.118.113.237        10.118.110.63         TCP      80     mmpft > 55630 [SYN,ACK] Seq=0 Ack=1 Win=49232 Len=0 TSval=62392984 TSecr=355216086 MSS=1460 WS=1 SACK_PERM=1
 42 30.571620000   10.118.110.63         10.118.113.237        TCP      68     55630 > mmpft [ACK] Seq=1 Ack=1 Win=5888 Len=0 TSval=355216086 TSecr=62392984
 43 30.572253000   10.118.110.63         10.118.113.237        DIAMETER 276    cmd=Capabilities-ExchangeRequest(257) flags=R--- appl=Diameter Common Messages(0) h2h=3f3197d e2e=e9200847
 44 30.572638000   10.118.113.237        10.118.110.63         TCP      68     mmpft > 55630 [ACK] Seq=1 Ack=209 Win=49232 Len=0 TSval=62392984 TSecr=355216086
 45 30.579815000   10.118.113.237        10.118.110.63         TCP      68     mmpft > 55603 [FIN,ACK] Seq=337 Ack=209 Win=49232 Len=0 TSval=62392985 TSecr=355208530
 46 30.579826000   10.118.110.63         10.118.113.237        TCP      56     55603 > mmpft [RST] Seq=209 Win=0 Len=0
 47 30.581517000   10.118.113.237        10.118.110.63         DIAMETER 312    cmd=Capabilities-ExchangeAnswer(257) flags=---- appl=Diameter Common Messages(0) h2h=3f3197d e2e=e9200847
 48 30.581553000   10.118.110.63         10.118.113.237        TCP      68     55630 > mmpft [ACK] Seq=209 Ack=245 Win=6912 Len=0 TSval=355216088 TSecr=62392985
 49 34.138766000   10.118.113.237        10.118.110.63         TCP      68     mmpft > 39679 [FIN,ACK] Seq=1 Ack=1 Win=49232 Len=0 TSval=62393341 TSecr=355193509
 50 34.138790000   10.118.110.63         10.118.113.237        TCP      56     39679 > mmpft [RST] Seq=1 Win=0 Len=0

解决方法

这是概念的粗略解释.

[ACK]是接收到先前发送的数据包的确认.

当主机要终止连接时,[FIN]由主机发送; TCP协议要求两个端点发送终止请求(即FIN).

所以,假设

主机A向主机B发送数据包
>然后主机B要关闭连接.
>主机B(取决于定时)可以用[FIN,ACK]响应,表示它接收到发送的数据包,并希望关闭会话.
主机A应该用[FIN,指示它接收到终止请求(ACK部分),并且它也将关闭连接(FIN部分).

然而,如果主机A想要在发送数据包后关闭会话,它将只发送一个[FIN]数据包(没有任何内容可以确认),但是主机B将以[FIN,ACK]响应(确认请求并以FIN响应).

最后,一些TCP堆栈执行半双工终止,这意味着它们可以发送[RST]而不是通常的[FIN,ACK].当主机主动关闭会话而不处理发送给它的所有数据时,会发生这种情况. Linux是一个只是这样的操作系统.

您可以找到更详细和全面的解释here.

（编辑：李大同）

【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容!