linux – 如果退出0结果,如何退出所有管理程序进程
发布时间:2020-12-13 17:08:06  所属栏目:Linux  来源:网络整理 
            导读:我和这样的主管一起运行docker container: Dockerfile CMD ["/run.sh"] run.sh #!/usr/bin/env bashexec supervisord -n 主管-serf.conf [group:job]programs=serf,producer[program:serf]command=/start-serf-agent.shnumprocs=1autostart=trueautorestart
                
                
                
            | 我和这样的主管一起运行docker container: 
  
  Dockerfile CMD ["/run.sh"] run.sh #!/usr/bin/env bash exec supervisord -n 主管-serf.conf [group:job] programs=serf,producer [program:serf] command=/start-serf-agent.sh numprocs=1 autostart=true autorestart=unexpected stopasgroup=true killasgroup=true stdout_logfile=/dev/stdout stdout_logfile_maxbytes=0 stderr_logfile=/dev/stderr stderr_logfile_maxbytes=0 start-serf-agent.sh #!/bin/bash exec serf agent --join=serf:7946 -tag role=producer 主管-servce.conf [program:producer] command=/start.sh numprocs=1 stopasgroup=true killasgroup=true stdout_logfile=/dev/stdout stdout_logfile_maxbytes=0 stderr_logfile=/dev/stderr stderr_logfile_maxbytes=0 start.sh #!/bin/bash
exec /producer --project=${NAME}生产者停止后,我得到了: producer_1 | 2016/02/29 21:59:50 [INFO] serf: EventMemberLeave: 7c4fbc80af97 172.19.0.2 producer_1 | 2016/02/29 21:59:51 INF 1 stopping producer_1 | 2016/02/29 21:59:51 INF 1 exiting router producer_1 | 2016-02-29 21:59:51,281 INFO exited: producer (exit status 0; expected) producer_1 | 2016/02/29 21:59:51 [INFO] agent: Received event: member-leave 但是serf-agent使容器保持运行状态.当生产者正确地完成他的工作状态0时,我想停止Docker容器.我试图将进程加入到一个组但似乎不起作用.伙计们,我跳过了什么?请帮帮我! 解决方法
 我解决了supervisor eventlistener的问题: 
  
  
  [program:worker] command=/start.sh priority=2 process_name=worker numprocs=1 stopasgroup=true killasgroup=true stdout_logfile=/dev/stdout stdout_logfile_maxbytes=0 stderr_logfile=/dev/stderr stderr_logfile_maxbytes=0 [eventlistener:worker_exit] command=/kill.py process_name=worker events=PROCESS_STATE_EXITED kill.py #!/usr/bin/env python
import sys
import os
import signal
def write_stdout(s):
   sys.stdout.write(s)
   sys.stdout.flush()
def write_stderr(s):
   sys.stderr.write(s)
   sys.stderr.flush()
def main():
   while 1:
       write_stdout('READYn')
       line = sys.stdin.readline()
       write_stdout('This line kills supervisor: ' + line);
       try:
               pidfile = open('/var/run/supervisord.pid','r')
               pid = int(pidfile.readline());
               os.kill(pid,signal.SIGQUIT)
       except Exception as e:
               write_stdout('Could not kill supervisor: ' + e.strerror + 'n')
       write_stdout('RESULT 2nOK')
if __name__ == '__main__':
   main()
   import sys
main issue I forgot to point to **process_name**也好文章process management in docker containers (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! | 
