asp.net-web-api2 – 通过http Post请求将XML发送到Web Api的问

发布时间：2020-12-16 09:12:54 所属栏目：asp.Net 来源：网络整理

导读：我想将以下 XML文档发送到我的Web Api 2控制器;但是,[FromBody]参数始终为null. 这是请求XML主体： razorInbound server="PortfolioExposureServer" request="lookupRiskPointRecord" callerRazorClient/caller responseModexml/responseMode body condition

我想将以下 XML文档发送到我的Web Api 2控制器;但是,[FromBody]参数始终为null.

这是请求XML主体：

<razorInbound server="PortfolioExposureServer" request="lookupRiskPointRecord">
  <caller>RazorClient</caller>
  <responseMode>xml</responseMode>
  <body>
    <conditions>
      <fromOffset>0</fromOffset>
      <top>100</top>
      <condition>
        <keyPath>
          <keyElement nodeOffset='1'>Currency</keyElement>
          <keyElement nodeOffset='2'>ID</keyElement>
        </keyPath>
        <lookupValue>USD</lookupValue>
      </condition>
    </conditions>
  </body>
</razorInbound>

使用Postman发送请求,如下：

POST /api/razorXmlRequest HTTP/1.1
Host: localhost:5000
Content-Type: application/xml
Cache-Control: no-cache
Postman-Token: 6ca91ebf-31e0-77f2-6f81-cb9993b69b1a

<razorInbound server="PortfolioExposureServer" request="lookupRiskPointRecord">
  <caller>RazorClient</caller>
  <responseMode>xml</responseMode>
  <body>
    <conditions>
      <fromOffset>0</fromOffset>
      <top>100</top>
      <condition>
        <keyPath>
          <keyElement nodeOffset='1'>Currency</keyElement>
          <keyElement nodeOffset='2'>ID</keyElement>
        </keyPath>
        <lookupValue>USD</lookupValue>
      </condition>
    </conditions>
  </body>
</razorInbound>

和Web Api 2控制器：

注意：param参数始终为null

我相信我需要一个正确的类定义才能正确映射XML请求,但我不确定如何构建它.

using System;
using System.Threading.Tasks;
using System.IO;
using System.Text;
using RazorServices;
using System.Net.Http;
using System.Web.Http;
using System.Xml.Linq;
using System.Net;
using System.Xml;

namespace RazorWebApi.Controllers
{
    [Route("api/razorXmlRequest")]
    public class RazorXmlRequestController : ApiController
    {
        public class RawXml {
            public string RazorXml { get; set; }
        }

        [HttpPost]
        public async Task<HttpResponseMessage> Post([FromBody]RawXml param )
        {
            HttpResponseMessage resp = new HttpResponseMessage(HttpStatusCode.OK);

            // code omitted...
			
            return resp;
        }
    }
}

顺便说一句,我们目前正在通过设置一个StreamReader对象来解决这个问题.Request.Content;但是在我的单元测试中,我需要发送我的xml作为参数.

[HttpPost]
        public async Task<HttpResponseMessage> Post()   // [FromBody]RawXml param )
        {
            HttpResponseMessage resp = new HttpResponseMessage(HttpStatusCode.OK);

            StreamReader sr = new StreamReader(await this.Request.Content.ReadAsStreamAsync(),Encoding.UTF8);
            string xml = sr.ReadToEnd();

            if (xml == null || xml.Length < 4)
            {
                throw new RazorServicesException("Invalid XML");
            }
            RazorSession cred = RzWebApi.Cred;
            string reply = await RzWebApi.RazorSrv.xmlRequests.Request(cred,xml);
            resp.Content = new StringContent(reply,System.Text.Encoding.UTF8,"text/plain");
            return resp;
        }

解决方法

最终解决方案是将Post param类型更改为XElement：

[Route("api/razorXmlRequest")]
public class RazorXmlRequestController : ApiController
{
    /// <summary>
    /// Raw Razor request XML 
    /// </summary>
    /// <returns>Razor reply message as text</returns>
    [HttpPost]
    public async Task<HttpResponseMessage> Post([FromBody]XElement xml)
    {
        HttpResponseMessage resp = new HttpResponseMessage(HttpStatusCode.OK);
        RazorSession cred = RzWebApi.Cred;
        string reply = await RzWebApi.RazorSrv.xmlRequests.Request(cred,xml);
        resp.Content = new StringContent(reply,"application/xml");
        return resp;
    }
}

这是直接工作,甚至没有像上面提到的那样提供XmlFormatter(@TusharJ,非常感谢你的输入).

（编辑：李大同）

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