asp.net-mvc-3 – 在MVC3中使用强类型视图时可能的模型继承?
我的模型中有以下设置:
namespace QuickTest.Models { public class Person { [Required] [Display(Name = "Full name")] public string FullName { get; set; } [Display(Name = "Address Line 1")] public virtual string Address1 { get; set; } } public class Sender : Person { [Required] public override string Address1 { get; set; } } public class Receiver : Person { } } 在我看来: @model QuickTest.Models.Person @{ ViewBag.Title = "Edit"; } <script src="@Url.Content("~/Scripts/jquery.validate.min.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.validate.unobtrusive.min.js")" type="text/javascript"></script> @using (Html.BeginForm()) { <fieldset> <legend>Person</legend> <div class="editor-label"> @Html.LabelFor(model => model.FullName) </div> <div class="editor-field"> @Html.EditorFor(model => model.FullName) @Html.ValidationMessageFor(model => model.FullName) </div> <div class="editor-label"> @Html.LabelFor(model => model.Address1) </div> <div class="editor-field"> @Html.EditorFor(model => model.Address1) @Html.ValidationMessageFor(model => model.Address1) </div> <div class="errors"> @Html.ValidationSummary(true) </div> <p> <input type="submit" value="Save" /> </p> </fieldset> } 启用客户端验证.但是,如果我将一个Sender类型的对象发送到View,则客户端验证不会检测到需要Address1字段.有没有办法让客户端验证在这种情况下工作? PS: <div class="editor-field"> @Html.Editor("Address1",Model.Address1) @Html.ValidationMessageFor(model => model.Address1) </div> 解决方法
您可以自定义验证器和元数据来自您的具体类,但该解决方案有几个移动部件,包括两个自定义元数据提供程序.
首先,创建一个自定义属性来装饰基类的每个属性.这是我们的自定义提供程序的标志所必需的,以指示何时需要进一步分析.这是属性: [AttributeUsage(AttributeTargets.All,Inherited = true,AllowMultiple = true)] public class BaseTypeAttribute : Attribute { } 接下来,创建一个继承自DataAnnotationsModelMetadataProvider的自定义ModelMetadataProvider: public class MyModelMetadataProvider : DataAnnotationsModelMetadataProvider { protected override ModelMetadata CreateMetadata( IEnumerable<Attribute> attributes,Type containerType,Func<object> modelAccessor,Type modelType,string propertyName) { var attribute = attributes.FirstOrDefault(a => a.GetType().Equals(typeof(BaseTypeAttribute))) as BaseTypeAttribute; if (attribute != null && modelAccessor != null) { var target = modelAccessor.Target; var containerField = target.GetType().GetField("container"); if (containerField == null) { var vdi = target.GetType().GetField("vdi").GetValue(target) as ViewDataInfo; var concreteType = vdi.Container.GetType(); return base.CreateMetadata(attributes,concreteType,modelAccessor,modelType,propertyName); } else { var container = containerField.GetValue(target); var concreteType = container.GetType(); var propertyField = target.GetType().GetField("property"); if (propertyField == null) { concreteType = base.GetMetadataForProperties(container,containerType) .FirstOrDefault(p => p.PropertyName == "ConcreteType").Model as System.Type; if (concreteType != null) return base.GetMetadataForProperties(container,concreteType) .FirstOrDefault(pr => pr.PropertyName == propertyName); } return base.CreateMetadata(attributes,propertyName); } } return base.CreateMetadata(attributes,containerType,propertyName); } } 然后,创建一个继承自DataAnnotationsModelValidatorProvider的自定义ModelValidatorProvider: public class MyModelMetadataValidatorProvider : DataAnnotationsModelValidatorProvider { protected override IEnumerable<ModelValidator> GetValidators(ModelMetadata metadata,ControllerContext context,IEnumerable<Attribute> attributes) { List<ModelValidator> vals = base.GetValidators(metadata,context,attributes).ToList(); var baseTypeAttribute = attributes.FirstOrDefault(a => a.GetType().Equals(typeof(BaseTypeAttribute))) as BaseTypeAttribute; if (baseTypeAttribute != null) { // get our parent model var parentMetaData = ModelMetadataProviders.Current.GetMetadataForProperties(context.Controller.ViewData.Model,metadata.ContainerType); // get the concrete type var concreteType = parentMetaData.FirstOrDefault(p => p.PropertyName == "ConcreteType").Model; if (concreteType != null) { var concreteMetadata = ModelMetadataProviders.Current.GetMetadataForProperties(context.Controller.ViewData.Model,Type.GetType(concreteType.ToString())); var concretePropertyMetadata = concreteMetadata.FirstOrDefault(p => p.PropertyName == metadata.PropertyName); vals = base.GetValidators(concretePropertyMetadata,attributes).ToList(); } } return vals.AsEnumerable(); } } 之后,在Global.asax.cs中的Application_Start中注册两个自定义提供程序: ModelValidatorProviders.Providers.Clear(); ModelValidatorProviders.Providers.Add(new MvcApplication8.Controllers.MyModelMetadataValidatorProvider()); ModelMetadataProviders.Current = new MvcApplication8.Controllers.MyModelMetadataProvider(); 现在,改变你的模型: public class Person { public Type ConcreteType { get; set; } [Required] [Display(Name = "Full name")] [BaseType] public string FullName { get; set; } [Display(Name = "Address Line 1")] [BaseType] public virtual string Address1 { get; set; } } public class Sender : Person { public Sender() { this.ConcreteType = typeof(Sender); } [Required] [Display(Name = "Address Line One")] public override string Address1 { get; set; } } public class Receiver : Person { } 请注意,基类具有新属性ConcreteType.这将用于指示哪个继承类已实例化此基类.每当继承类具有覆盖基类中元数据的元数据时,继承类的构造函数应该设置基类ConcreteType属性. 现在,即使您的视图使用基类,特定于任何具体继承类的属性也将出现在视图中,并将影响模型的验证. 此外,您应该能够将View转换为Person类型的模板,并将该模板用于使用基类的任何实例或从中继承. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
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