ASP.NET MVC 3的jquery ajax表单

Ajax.BeginForm() is this then MvcAjax or Jquery?

默认情况下是jquery.您需要引用jquery.unobtrusive-ajax.js脚本才能使其工作.

Or would I use Html.BeginForm() and register something like $.post on the click event of the Form.

这是另一种选择.就我个人而言

I assume that it is correct,that I am posting to the create action of the commentscontroller and I would use the JsonModelBinder to transform it to a model. After that I would return Json and would append it to my comments list…

JsonModelBinder已经在ASP.NET MVC 3中引入,它允许您将JSON字符串发送到将被映射回视图模型的控制器操作.例如,如果您有以下视图模型：

public class PersonViewModel
{
    public string Name { get; set; }
    public int Age { get; set; }
}

并采取以下行动：

public ActionResult Foo(PersonViewModel person) 
{
    ...    
}

在AJAX中调用它的传统方式是：

$.ajax({
    url: '@Url.Action("foo")',type: 'POST',data: { name: 'john',age: 20 },success: function(result) {
        // TODO:
    }
});

并且在ASP.NET MVC 3中,您可以发送一个JSON作为请求参数,该参数将绑定到PersonViewModel操作参数：

$.ajax({
    url: '@Url.Action("foo")',contentType: 'application/json',data: JSON.stringify({ name: 'john',age: 20 }),success: function(result) {
        // TODO:
    }
});