asp.net-mvc – 如何继承ASP.NET MVC控制器并仅更改视图？

几点.如果您知道所有要返回的内容,则可以将返回值键入ViewResult.然后,您可以从重写的实现中查询该值.更重要的是,根据MVC v1源代码,调用View(object)只需在控制器上设置ViewData.Model,然后构造一个ViewResult.

Controller.cs：440

protected internal ViewResult View(object model) {
    return View(null /* viewName */,null /* masterName */,model);
}

Controller.cs：456

protected internal virtual ViewResult View(string viewName,string masterName,object model) {
    if (model != null) {
        ViewData.Model = model;
    }

    return new ViewResult {
        ViewName = viewName,MasterName = masterName,ViewData = ViewData,TempData = TempData
    };
}

所以你需要做的就是调用base方法并调用View(string).

namespace BaseControllers
{
    public class CoolController
    {
        public virtual ViewResult Get() 
        {
            var awesomeModel = new object();
            return View(awesomeModel);
        }
    }
}

public class CoolController : BaseControllers.CoolController
{
    public override ViewResult Get() 
    {
        var ignoredResult = base.Get();
        // ViewData.Model now refers to awesomeModel
        return View("NotGet");
    }
}

当然,您浪费CPU周期来构建您忽略的ViewResult.所以你可以这样做：

public class CoolController : BaseControllers.CoolController
{
    public override ViewResult Get() 
    {
        var baseResult = base.Get();
        baseResult.ViewName = "NotGet";
        return baseResult;
    }
}

如果您的基本控制器返回ActionResult,则必须在更改ViewName之前将其强制转换为ViewResult.