python – 使用PIL将二进制字符串转换为图像
发布时间:2020-12-20 13:43:10 所属栏目:Python 来源:网络整理
导读:所以,我要做的是让PIL根据二进制字符串创建一个图像. 一些背景故事: from PIL import Imagevalue = "0110100001100101011011000110110001101111"vdiv = [value[i:i+8] for i in range(0,len(value),8)] ^这将从二进制字符串中创建一个字节列表. [‘01101000
所以,我要做的是让PIL根据二进制字符串创建一个图像.
一些背景故事: from PIL import Image value = "0110100001100101011011000110110001101111" vdiv = [value[i:i+8] for i in range(0,len(value),8)] ^这将从二进制字符串中创建一个字节列表. [‘01101000′,’01100101’,…..] def diff(inp): if inp == '1': return (0,0) if inp == '0': return (255,255,255) else: pass ^这会返回每个相应位的颜色元组,如果我调用: for i in vdiv: for i2 in i: print diff(i2) 它将为列出的字节中的每个位打印每个颜色元组. (0,0)(0,0)(255,255)…… 我想知道的是,如何让PIL创建像素与二进制字符串匹配的图像? 这是它应该是什么样子: 到目前为止我对PIL的看法: img = Image.new( 'RGB',(8,len(vdiv)),"white") pixels = img.load() ## for x in range(img.size[0]): for y in range(img.size[1]): for i in vdiv: for i2 in i: pixels[x,y] = diff(i2) #Creates a black image. What do? ## img.show() 它是我在范围内的x位.我搞不清楚了. 解决方法
你可以使用img.putdata:
import Image value = "0110100001100101011011000110110001101111" cmap = {'0': (255,255),'1': (0,0)} data = [cmap[letter] for letter in value] img = Image.new('RGB',len(value)//8),"white") img.putdata(data) img.show() 如果你有NumPy,你可以使用Image.fromarray: import Image import numpy as np value = "0110100001100101011011000110110001101111" carr = np.array([(255,(0,0)],dtype='uint8') data = carr[np.array(map(int,list(value)))].reshape(-1,8,3) img = Image.fromarray(data,'RGB') img.save('/tmp/out.png','PNG') 但是这个timeit测试建议使用putdata更快: value = "0110100001100101011011000110110001101111"*10**5 def using_fromarray(): carr = np.array([(255,dtype='uint8') data = carr[np.array(map(int,3) img = Image.fromarray(data,'RGB') return img def using_putdata(): cmap = {'0': (255,0)} data = [cmap[letter] for letter in value] img = Image.new('RGB',"white") img.putdata(data) return img In [79]: %timeit using_fromarray() 1 loops,best of 3: 1.67 s per loop In [80]: %timeit using_putdata() 1 loops,best of 3: 632 ms per loop (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |