如何减少类似的if语句python?
发布时间:2020-12-20 13:05:27 所属栏目:Python 来源:网络整理
导读:我正在开发一个项目,我需要将数值更改为字母字符,目前,我有: if finposb == "2": finposb = "a"if finposb == "3": finposb = "b"if finposb == "4": finposb = "c"if finposb == "5": finposb = "d"if finposb == "6": finposb = "e"if finposb == "7": fi
我正在开发一个项目,我需要将数值更改为字母字符,目前,我有:
if finposb == "2": finposb = "a" if finposb == "3": finposb = "b" if finposb == "4": finposb = "c" if finposb == "5": finposb = "d" if finposb == "6": finposb = "e" if finposb == "7": finposb = "f" if finposb == "8": finposb = "g" if finposb == "9": finposb = "h" 我想知道是否有办法将其减少到更短的代码行,谢谢! 解决方法letters='abcdefghijklmnopqrstuvwxyz' finposb=letters[int(finposb)-2] 这应该工作,不需要字典.如果你想要它更短: finposb='abcdefghijklmnopqrstuvwxyz'[int(finposb)-2] (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |