如何在Python中实现“if if”？

发布时间：2020-12-20 13:05:10 所属栏目：Python 来源：网络整理

导读：我想在概念上实现以下内容： if condition1: action1()also if condition2: action2()also if condition3: action3()also if condition4: action4()also if condition5: action5()also if condition6: action6()else: print("None of the conditions was met

我想在概念上实现以下内容：

if condition1:
    action1()
also if condition2:
    action2()
also if condition3:
    action3()
also if condition4:
    action4()
also if condition5:
    action5()
also if condition6:
    action6()
else:
    print("None of the conditions was met.")

实现这样的逻辑的合理而明确的方法是什么？怎么可能将else绑定到多个if语句？我是否会被迫创建一个布尔来跟踪事物？

解决方法

好的,根据澄清,这样的事情会很好：

class Accumulator(object):
    none = None
    def also(self,condition):
        self.none = not condition and (self.none is None or self.none)
        return condition

acc = Accumulator()
also = acc.also

if also(condition1):
    action1()
if also(condition2):
    action2()
if also(condition3):
    action3()
if also(condition4):
    action4()
if acc.none:
    print "none passed"

您可以扩展它以获取有关if语句执行的其他信息：

class Accumulator(object):
    all = True
    any = False
    none = None
    total = 0
    passed = 0
    failed = 0

    def also(self,condition):
        self.all = self.all and condition
        self.any = self.any or condition
        self.none = not condition and (self.none is None or self.none)
        self.total += 1
        self.passed += 1 if condition else self.failed += 1 
        return condition

（编辑：李大同）

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