将字符串拆分为Python中的列表
发布时间:2020-12-20 12:31:11 所属栏目:Python 来源:网络整理
导读:我有一个文本文件,我想放入列表. 文本文件如下所示: New Distribution Votes Rank Title 0000000125 1196672 9.2 The Shawshank Redemption (1994) 0000000125 829707 9.2 The Godfather (1972) 0000000124 547511 9.0 The Godfather: Part II (1974) 00000
我有一个文本文件,我想放入列表.
文本文件如下所示: New Distribution Votes Rank Title 0000000125 1196672 9.2 The Shawshank Redemption (1994) 0000000125 829707 9.2 The Godfather (1972) 0000000124 547511 9.0 The Godfather: Part II (1974) 0000000124 1160800 8.9 The Dark Knight (2008) 我试过用这段代码拆分列表: x = open("ratings.list.txt","r") movread = x.readlines() x.close() s = raw_input('Search: ') for ns in movread: if s in ns: print(ns.split()[0:100]) 输出: Search: #1 Single ['1000000103','56','6.3','"#1','Single"','(2006)'] 但它并没有给我我想要的输出 它分裂在标题之间的空格上. 如何在不破坏标题的情况下将其拆分为列表? 预期产量: Search: #1 Single Distribution Votes Rank Title ['1000000103','"#1 Single" (2006)'] 解决方法
split()接受一个可选的maxsplit参数:
In Python 3: >>> s = " 0000000125 1196672 9.2 The Shawshank Redemption (1994)" >>> s.split() ['0000000125','1196672','9.2','The','Shawshank','Redemption','(1994)'] >>> s.split(maxsplit=3) ['0000000125','The Shawshank Redemption (1994)'] In Python 2,您需要将maxsplit参数指定为位置参数: >>> s = " 0000000125 1196672 9.2 The Shawshank Redemption (1994)" >>> s.split(None,3) ['0000000125','The Shawshank Redemption (1994)'] (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |