python – 如何检查循环范围的重叠(重叠的年度循环周期)
我试图找到一个优雅的算法,以检查两个年度重复周期是否重叠.这个时期与年份无关,但一年可能总是闰年.
例如,期间A =(3月1日至5月1日)和期间B =(4月1日至9月1日)重叠. 但是,我发现这比我预想的要困难得多.复杂性来自于跨越年底的时期. 我有一个有效的解决方案(参见下面的doOverlap(A,B)方法),但我发现它令人沮丧. # for the rest of the MWE context code,see further # WORKING,but a bit convulted def doesOverlap(A,B): '''returns True if yearly period A and B have overlapping dates''' # list to track if day in year is part of a period A # (this could probably be done a bit cheaper with a dictionary of tuples,but not relevant for my question) yeardayCovered = [False for x in range(366)] # leap year # mark the days of A for d in range(A.start,A.start + A.length): yeardayCovered[d % 366] = True # now check each of the days in B with A for d in range(B.start,B.start + B.length): if yeardayCovered[d % 366]: return True return False 我相信应该可以用更少的支票和更优雅的方式来做到这一点.我已经尝试将其中一个开始日设置为零偏移,应用一些模运算符,然后是常规(非循环)范围重叠检查(Algorithm to detect overlapping periods).但我还没有为我的所有测试用例工作. #NOT WORKING CORRECTLY!! def doesOverlap(A,B): '''determines if two yearly periods have overlapping dates''' Astart = A.start Astop = A.stop Bstart = B.start Bstop = B.stop # start day counting at Astart,at 0 offset = Astart Astart = 0 Astop = (Astop - offset) % 366 Bstart = (Bstart - offset) % 366 Bstop = (Bstop - offset) % 366 # overlap? # https://stackoverflow.com/a/13513973 return (Astart <= Bstop and Bstart <= Astop) 注意:我已经用Python完成了代码,但理想情况下解决方案应该不是特定于Python的(即不使用通常只在Python中可用的函数,而不是在C或C#中) # MWE (Minimal Working Example) import datetime import unittest class TimePeriod: def __init__(self,startDay,startMonth,stopDay,stopMonth): self.startDay = startDay self.startMonth = startMonth self.stopDay = stopDay self.stopMonth = stopMonth def __repr__(self): return "From " + str(self.startDay) + "/" + str(self.startMonth) + " to " + str(self.stopDay) + "/" + str(self.stopMonth) def _dayOfYear(self,d,m,y=2012): '''2012 = leap year''' date1 = datetime.date(year=y,day=d,month=m) return date1.timetuple().tm_yday @property def start(self): '''day of year of start of period,zero-based for easier modulo operations! ''' return self._dayOfYear(self.startDay,self.startMonth) - 1 @property def stop(self): '''day of year of stop of period,zero-based for easier modulo operations! ''' return self._dayOfYear(self.stopDay,self.stopMonth) - 1 @property def length(self): '''number of days in the time period''' _length = (self.stop - self.start) % 366 + 1 return _length def doesOverlap(A,B): # code from above goes here class TestPeriods(unittest.TestCase): pass def test_generator(a,b,c): def test(self): self.assertEqual(doesOverlap(a,b),c) return test if __name__ == '__main__': #some unit tests,probably not complete coverage of all edge cases though tests = [["max",TimePeriod(1,1,31,12),1),True],["BinA",3,11),5,10),["BoverEndA",2),TimePeriod(10,3),["BafterA",TimePeriod(2,2,False],["sBoutA",12,5),6,7),["sBoverBeginA",11,10,["sBinA",["sBinA2",["sBinA3",["Leap",TimePeriod(29,4),["BtouchEndA",True]] for i,t in enumerate(tests): test_name = 'test_%s' % t[0] test = test_generator(t[1],t[2],t[3]) setattr(TestPeriods,test_name,test) # unittest.main() suite = unittest.TestLoader().loadTestsFromTestCase(TestPeriods) unittest.TextTestRunner(verbosity=2).run(suite) 解决方法def overlap(a0,a1,b0,b1): 首先,如果在开始日期之前结束,则可以通过调整结束日期将“年”圈中的间隔“提升”到时间“线”… if a1 < a0: a1 += 365 if b1 < b0: b1 += 365 如果两个规则间隔相交,则存在交叉点 if a1 > b0 and a0 < b1: return True 或者如果他们确实移动[a0 … a1 [前进一年或后退一年 if a1+365 > b0 and a0+365 < b1: return True if a1-365 > b0 and a0-365 < b1: return True 否则没有交集 return False (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |