python – 将特定文件复制到新文件夹,同时保留原始子目录树
发布时间:2020-12-20 11:49:16 所属栏目:Python 来源:网络整理
导读:我有一个包含许多子目录的大型目录,我正在尝试排序,我正在尝试将特定文件类型复制到新文件夹,但我想维护原始子目录. def copyFile(src,dest):try: shutil.copy(src,dest)except shutil.Error as e: print('Error: %s' % e)except IOError as e: print('Error
我有一个包含许多子目录的大型目录,我正在尝试排序,我正在尝试将特定文件类型复制到新文件夹,但我想维护原始子目录.
def copyFile(src,dest): try: shutil.copy(src,dest) except shutil.Error as e: print('Error: %s' % e) except IOError as e: print('Error: %s' % s.strerror) for root,directories,files in os.walk(directory): for directoryname in directories: dirpath = os.path.join(root,directoryname) dir_paths.append(dirpath) dir_names.append(directoryname) if not os.listdir(dirpath): #Cheching if directory is empty print("Empty") EmptyDirs.append(directoryname) #Add directory name to empty directory list EmptyDirPath.append(dirpath) else: pass for filename in files: filepath = os.path.join(root,filename) file_paths.append(filepath) file_names.append(filename) if filename.lower().endswith(".sldasm"): print(filename.encode('utf8')) SolidModels.append(filename) copyFile(filepath,dest) elif filename.lower().endswith(".sldprt"): print(filename.encode('utf8')) SolidModels.append(filename) copyFile(filepath,dest) else: pass 这是我现在使用的代码,但它只是复制文件而不复制它们最初所在的子目录,因此它们在新文件夹中完全没有组织. 这是使用copytree的新代码,但是现在特定文件不会复制,只有子目录才能复制. def copytree(src,dst,symlinks=False,ignore=None): names = os.listdir(src) if ignore is not None: ignored_names = ignore(src,names) else: ignored_names = set() os.makedirs(dst) errors = [] for name in names: if name in ignored_names: continue srcname = os.path.join(src,name) dstname = os.path.join(dst,name) try: if symlinks and os.path.islink(srcname): linkto = os.readlink(srcname) os.symlink(linkto,dstname) elif os.path.isdir(srcname): copytree(srcname,dstname,symlinks,ignore) else: if src is "*.sldasm": copy2(srcname,dstname) elif src is "*.sldprt": copy2(srcname,dstname) except (IOError,os.error) as why: errors.append((srcname,str(why))) 解决方法
您可以使用其可选的ignore关键字参数,使用
shutil.copytree() 函数执行所需操作.棘手的部分是,如果给定,它必须是一个可调用的,它返回每个目录中不应复制的内容,而不是应该复制的内容.
但是,可以编写类似于 首先返回的函数通过 #!/usr/bin/env python # -*- coding: utf-8 -*- # Works in Python 2.7 & 3.x import fnmatch from os.path import isdir,join def include_patterns(*patterns): """ Function that can be used as shutil.copytree() ignore parameter that determines which files *not* to ignore,the inverse of "normal" usage. This is a factory function that creates a function which can be used as a callable for copytree()'s ignore argument,*not* ignoring files that match any of the glob-style patterns provided. ?patterns’ are a sequence of pattern strings used to identify the files to include when copying the directory tree. Example usage: copytree(src_directory,dst_directory,ignore=include_patterns('*.sldasm','*.sldprt')) """ def _ignore_patterns(path,all_names): # Determine names which match one or more patterns (that shouldn't be # ignored). keep = (name for pattern in patterns for name in fnmatch.filter(all_names,pattern)) # Ignore file names which *didn't* match any of the patterns given that # aren't directory names. dir_names = (name for name in all_names if isdir(join(path,name))) return set(all_names) - set(keep) - set(dir_names) return _ignore_patterns if __name__ == '__main__': from shutil import copytree,rmtree import os src = r'C:volsFilesPythonLibStack Overflow' dst = r'C:volsTemptemptest' # Make sure the destination folder does not exist. if os.path.exists(dst) and os.path.isdir(dst): print('removing existing directory "{}"'.format(dst)) rmtree(dst,ignore_errors=False) copytree(src,ignore=include_patterns('*.png','*.gif')) print('done') (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |