python – 从两个列表构建字典
发布时间:2020-12-20 11:47:31 所属栏目:Python 来源:网络整理
导读:参见英文答案 Convert two lists into a dictionary in Python????????????????????????????????????15个 我有两个列表,如下所示(长度相等) cities = ['New York','Tokyo','Moscow','London']altitudes = ['13000','12000','11000','9000'] 我想构建一个字典
参见英文答案 >
Convert two lists into a dictionary in Python????????????????????????????????????15个
我有两个列表,如下所示(长度相等) cities = ['New York','Tokyo','Moscow','London'] altitudes = ['13000','12000','11000','9000'] 我想构建一个字典如下 mydict = {x : y for x in cities and y in altitudes} 我的python解释器说无效的语法.为什么这个无效?我该怎么做? 解决方法thing = {city:altitude for city,altitude in zip(cities,altitudes)} 理解期望单个可迭代(列表等)循环.因此,要解决此问题,首先需要将两个列表转换为单个列表,然后将该列表提供给将其转换为dict的理解. 将上面的线分开一点,首先使用python的zip来聚合元素 list_of_tuples = zip(cities,altitudes) 然后你将其转换为dict: thing = {city: alt for city,alt in list_of_tuples} 或者更简单 thing = dict(list_of_tuples) (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |