python – 将列表转换为多值dict

发布时间：2020-12-20 11:46:47 所属栏目：Python 来源：网络整理

导读：我有一个列表： pokemonList = ['Ivysaur','Grass','Poison','','Venusaur','Charmander','Fire',''...] 请注意,模式是’口袋妖怪名称’,’它的类型’,”…下一个口袋妖怪口袋妖怪有单一和双重形式.我如何对此进行编码,以便每个口袋妖怪(键)都将其各自的类

我有一个列表：

pokemonList = ['Ivysaur','Grass','Poison','','Venusaur','Charmander','Fire',''...]

请注意,模式是’口袋妖怪名称’,’它的类型’,”…下一个口袋妖怪

口袋妖怪有单一和双重形式.我如何对此进行编码,以便每个口袋妖怪(键)都将其各自的类型应用为其值？

到目前为止我得到了什么：

types = ("","Grass","Poison","Fire","Flying","Water","Bug","Dark","Fighting","Normal","Ground","Ghost","Steel","Electric","Psychic","Ice","Dragon","Fairy")
pokeDict = {}
    for pokemon in pokemonList:
        if pokemon not in types:
            #the item is a pokemon,append it as a key
        else:
            for types in pokemonList:
                #add the type(s) as a value to the pokemon

正确的字典将如下所示：

{Ivysaur: ['Grass','Poison'],Venusaur['Grass',Charmander:['Fire']}

解决方法

只需迭代列表并适当地构造dict的项目.

current_poke = None
for item in pokemonList:
    if not current_poke:
        current_poke = (item,[])
    elif item:
        current_poke[1].append(item)
    else:
        name,types = current_poke
        pokeDict[name] = types
        current_poke = None

（编辑：李大同）

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