Python csv错误:序列预期
发布时间:2020-12-20 11:34:38 所属栏目:Python 来源:网络整理
导读:我使用psycopg2连接 postgresql和 python,这是我的脚本, import sys#set up psycopg2 environmentimport psycopg2#driving_distance modulequery = """ select * from driving_distance ($$ select gid as id,start_id::int4 as source,end_id::int4 as targ
我使用psycopg2连接
postgresql和
python,这是我的脚本,
import sys #set up psycopg2 environment import psycopg2 #driving_distance module query = """ select * from driving_distance ($$ select gid as id,start_id::int4 as source,end_id::int4 as target,shape_leng::double precision as cost from network $$,%s,%s ) """ #make connection between python and postgresql conn = psycopg2.connect("dbname = 'TC_routing' user = 'postgres' host = 'localhost' password = '****'") cur = conn.cursor() #count rows in the table cur.execute("select count(*) from network") result = cur.fetchone() k = result[0] + 1 #run loops rs = [] i = 1 while i <= k: cur.execute(query,(i,1000000,False,False)) rs.append(cur.fetchall()) i = i + 1 h = 0 ars = [] element = list(rs) while h <= 15: rp = element[0][h][2] ars.append(rp) h = h + 1 print ars conn.close() 输出很好, [0.0,11810.7956476379,16018.6818979217,18192.3576530232,21507.7366792666,25819.1955059578,26331.2523709618,49447.0908955008,28807.7871013087,39670.8579371438,42723.0239515299,38719.7320396044,38265.4435766971,40744.8813155033,43770.2158657742,46224.8748774639] 但如果我在下面添加一些行以将结果导出到csv文件,我收到此错误, import csv with open('test.csv','wb') as f: writer = csv.writer(f,delimiter = ',') for row in ars: writer.writerow(row) [0.0,46224.8748774639] Traceback (most recent call last): File "C:/Users/Heinz/Desktop/python_test/distMatrix_test.py",line 54,in <module> writer.writerow(row) Error: sequence expected 如何解决这个问题? 我在Windows 8.1 x64下使用python 2.7.6和pyscripter.随便给我任何建议,非常感谢! 解决方法import csv with open('test.csv','wb') as f: writer = csv.writer(f,') for row in ars: writer.writerow(row) ars只是一个列表.所以你的for循环不会从ars中提取一行.它从ars列表中获取一个元素,并尝试将其写为一行. 尝试替换它 for row in ars: writer.writerow([row]) 这会将每个元素写成csv文件中的一行. 或者如果你想在输出中有一行,那么就不要使用for循环,而是使用 writer.writerow(ars) (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
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