获取在python中操作原始列表的多维列表
发布时间:2020-12-20 11:31:47 所属栏目:Python 来源:网络整理
导读:我想根据磁贴分组文件列表. files = ['tile1_band1','tile1_band2','tile2_band1','tile2_band2']tiles = [file[0:5] for file in files]for tile in tiles: new_files = [file for file in files if tile in file] print (new_files) 结果应完全如下(二维列
我想根据磁贴分组文件列表.
files = ['tile1_band1','tile1_band2','tile2_band1','tile2_band2'] tiles = [file[0:5] for file in files] for tile in tiles: new_files = [file for file in files if tile in file] print (new_files) 结果应完全如下(二维列表): [['tile1_band1','tile1_band2'],['tile2_band1','tile2_band2']] 解决方法
使用
zip builtin并在切片中放一步:
In [26]: a = range(10) In [27]: zip(a[::2],a[1::2]) Out[27]: [(0,1),(2,3),(4,5),(6,7),(8,9)] (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |