Python Ephem / Datetime计算

发布时间：2020-12-20 11:13:21 所属栏目：Python 来源：网络整理

导读：输出应该将第一个日期处理为“日”,将第二个日期作为“夜晚”处理.我现在已经玩了几个小时了,无法弄清楚我做错了什么.有任何想法吗？编辑我认为问题是由于我的日期比较实现输出： $python time_of_day.py* should be day:event date: 2010/4/6 16:00:59pr

输出应该将第一个日期处理为“日”,将第二个日期作为“夜晚”处理.我现在已经玩了几个小时了,无法弄清楚我做错了什么.有任何想法吗？

编辑
我认为问题是由于我的日期比较实现

输出：

$python time_of_day.py
* should be day:
event date:  2010/4/6 16:00:59
prev rising:  2010/4/6 09:24:24
prev setting:  2010/4/5 23:33:03
next rise:  2010/4/7 09:22:27
next set:  2010/4/6 23:34:27
day
* should be night:
event date:  2010/4/6 00:01:00
prev rising:  2010/4/5 09:26:22
prev setting:  2010/4/5 23:33:03
next rise:  2010/4/6 09:24:24
next set:  2010/4/6 23:34:27
day

time_of_day.py

import datetime
import ephem # install from http://pypi.python.org/pypi/pyephem/

#event_time is just a date time corresponding to an sql timestamp
def type_of_light(latitude,longitude,event_time,utc_time,horizon):

  o = ephem.Observer()
  o.lat,o.long,o.date,o.horizon = latitude,horizon

  print "event date ",o.date

  print "prev rising: ",o.previous_rising(ephem.Sun())
  print "prev setting: ",o.previous_setting(ephem.Sun())
  print "next rise: ",o.next_rising(ephem.Sun())
  print "next set: ",o.next_setting(ephem.Sun())


  if o.previous_rising(ephem.Sun()) <= o.date <= o.next_setting(ephem.Sun()):
    return "day"
  elif o.previous_setting(ephem.Sun()) <= o.date <= o.next_rising(ephem.Sun()):
    return "night"
  else:
    return "error"


print "should be day: ",type_of_light('45.959','-66.6405','2010/4/6 16:01','-4','-6')

print "should be night: ",'2010/4/6 00:01','-6')

解决方法

o.date将始终位于o.previous_settings和o.next_rising;)之间,因此您可以这样检查：

if o.previous_rising(ephem.Sun()) > o.previous_setting(ephem.Sun()):
  return "day"
elif:
  return "night"

（编辑：李大同）

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