day12：闭包函数&匿名函数(lambda)

def songyunjie_family():
    father = "王健林"
     f_hobby():
        print(这是我爸爸{}".format(father))   # 内函数使用了外函数的局部变量father
    return f_hobby  外函数把内函数返回出来了

 mashengping_family():
    father = 马云"
    jiejie = 马蓉
    meimei = 马诺
    money =1000

     jiejie():
        nonlocal money
        money-=700
        还剩下{}元.format(money))
     meimei():
        nonlocal money
        money-=200
         big_master():
        return (jiejie,meimei)
     big_master

func = mashengping_family()
print(func)  <function mashengping_family.<locals>.big_master at 0x000001F4CB0F5620>

 返回的是元组
tup = func()
print(tup)  (<function mashengping_family.<locals>.jiejie at 0x0000013D5B175158>,<function mashengping_family.<locals>.meimei at 0x0000013D5B175268>)

 获取姐姐
jiejie = tup[0]
 获取妹妹
meimei = tup[1]

 big_master 是闭包函数,是直接被mashengping_family返回出来的
# jiejie,meimei 是通过big_master间接被返回到函数外面的

 调用妹妹
meimei()  还剩下800元 调用姐姐
jiejie()  还剩下100元


 获取闭包函数所使用的变量  __closure__
res = func.__closure__
print(res)  (<cell at 0x000001AF2B5A76A8: function object at 0x000001AF2B645158>,<cell at 0x000001AF2B5A76D8: function object at 0x000001AF2B645268>)

 cell_contents 用来获取单元格对象当中的闭包函数
jiejie = res[0].cell_contents  <function mashengping_family.<locals>.jiejie at 0x0000019161005158>
meimei = res[1].cell_contents  <function mashengping_family.<locals>.meimei at 0x0000019161005268>

i = jiejie.__closure__[0]  <cell at 0x0000020E9B977708: int object at 0x0000000054928CD0>
j = meimei. <cell at 0x0000020E9B977708: int object at 0x0000000054928CD0>

a = jiejie.__closure__[0].cell_contents  100
b = meimei. 100

 outer(val):
     inner(num):
        return val+num
     inner

func = outer(10)  func = inner
res = func(15)  res = func(15) =inner(15)
 25
"""
10实参-->val形参
因为内函数inner是闭包函数 使用了外函数val
那么该变量val生命周期被延长 没有随着函数调用的结束而释放
res = inner(15) => return val+num =>10+15 =>25
"""

 模拟鼠标点击次数
num = 0
 click_num():
    global num
    num += 1
    print(num)

click_num()  1
click_num()  2
click_num()  3
num = 100
click_num()  101
click_num()  102

'''
很显然,这样是不行的,定义了全局变量100后,值就从100开始加了.
想一个办法,让其就算在中间插入num=100也没用
'''

 解决方案
 click_num():
    num=0
     func():
        nonlocal num
        num+=1
        (num)
     func

func = click_num()
func()  1
func()  2
num = 1000
func()  3
func()  4
func()  5

 1.无参的lambda 表达式
 func():
    return 123"
    
 改写
func = lambda : 
res =print(res)

 2.有参的lambda 表达式
 func(n):
     type(n)
    
 改写    
func = lambda n : type(n)
print(  func([1,2,3])  )

if n % 2 == 0:
        偶数else:
        奇数        
        
func = lambda n : " if n % 2 == 0 else 
res = func(17)
print(res)

语法:
    真值 if 条件表达式 else 假值  如果条件表达式为真,返回真值,否则返回假值
"""
n = 16
res = "
print(res)

 小练习,传递两个数,返回较大的那一个
 func(x,y):
    if x>y:
         x
     y
        
func = lambda x,y : x if x>y  y
res = func(200,100print(res)