Python实现 深度优先算法生成迷宫
发布时间:2020-12-17 17:27:00 所属栏目:Python 来源:网络整理
导读:今天PHP站长网 52php.cn把收集自互联网的代码分享给大家,仅供参考。 import random #warning: x and y confusing sx = 10 sy = 10 dfs = [[0 for col in range(sx)] for row in range(sy)] maze = [[' ' for col in rang
以下代码由PHP站长网 52php.cn收集自互联网 现在PHP站长网小编把它分享给大家,仅供参考 import random #warning: x and y confusing sx = 10 sy = 10 dfs = [[0 for col in range(sx)] for row in range(sy)] maze = [[' ' for col in range(2*sx+1)] for row in range(2*sy+1)] #1:up 2:down 3:left 4:right operation = {1:(0,-1),2:(0,1),3:(-1,0),4:(1,0)} direction = [1,2,3,4] stack = [] for i in range(2*sx+1): if i%2 == 0: for j in range(2*sx+1): maze[i][j] = '#' for i in range(2*sy+1): if i%2 == 0: for j in range(2*sy+1): maze[j][i] = '#' def show(graph): for i in graph: for j in i: print j,print def showRouter(stack): RGragh = [[0 for col in range(sx)] for row in range(sy)] for (x,y) in stack: RGragh[y][x] = 1 show(RGragh) print def generateMaze(start): x,y = start dfs[y][x] = 1 random.shuffle(direction) for d in direction: px,py = (x + y for x,y in zip(start,operation[d])) if px < 0 or px >= sx or py < 0 or py >= sy: pass else: if dfs[py][px] is not 1: mx = 2*x + 1 my = 2*y + 1 if d == 1: maze[my-1][mx] = ' ' elif d == 2: maze[my+1][mx] = ' ' elif d == 3: maze[my][mx-1] = ' ' elif d == 4: maze[my][mx+1] = ' ' generateMaze((px,py)) generateMaze((0,0)) show(dfs) show(maze) 以上内容由PHP站长网【52php.cn】收集整理供大家参考研究 如果以上内容对您有帮助,欢迎收藏、点赞、推荐、分享。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |