python数据结构之链表详解
数据结构是计算机科学必须掌握的一门学问,之前很多的教材都是用C语言实现链表,因为c有指针,可以很方便的控制内存,很方便就实现链表,其他的语言,则没那么方便,有很多都是用模拟链表,不过这次,我不是用模拟链表来实现,因为python是动态语言,可以直接把对象赋值给新的变量。 好了,在说我用python实现前,先简单说说链表吧。在我们存储一大波数据时,我们很多时候是使用数组,但是当我们执行插入操作的时候就是非常麻烦,看下面的例子,有一堆数据1,2,3,5,6,7我们要在3和5之间插入4,如果用数组,我们会怎么做?当然是将5之后的数据往后退一位,然后再插入4,这样非常麻烦,但是如果用链表,我就直接在3和5之间插入4就行,听着就很方便。 那么链表的结构是怎么样的呢?顾名思义,链表当然像锁链一样,由一节节节点连在一起,组成一条数据链。 链表的节点的结构如下: data为自定义的数据,next为下一个节点的地址。 链表的结构为,head保存首位节点的地址: 接下来我们来用python实现链表 python实现链表 首先,定义节点类Node: class Node: ''' data: 节点保存的数据 _next: 保存下一个节点对象 ''' def __init__(self,data,pnext=None): self.data = data self._next = pnext def __repr__(self): ''' 用来定义Node的字符输出, print为输出data ''' return str(self.data) 然后,定义链表类: 链表要包括: 属性: 链表头:head 链表长度:length 方法: 判断是否为空: isEmpty() def isEmpty(self): return (self.length == 0 增加一个节点(在链表尾添加): append() def append(self,dataOrNode): item = None if isinstance(dataOrNode,Node): item = dataOrNode else: item = Node(dataOrNode) if not self.head: self.head = item self.length += 1 else: node = self.head while node._next: node = node._next node._next = item self.length += 1 删除一个节点: delete() #删除一个节点之后记得要把链表长度减一 def delete(self,index): if self.isEmpty(): print "this chain table is empty." return if index < 0 or index >= self.length: print 'error: out of index' return #要注意删除第一个节点的情况 #如果有空的头节点就不用这样 #但是我不喜欢弄头节点 if index == 0: self.head = self.head._next self.length -= 1 return #prev为保存前导节点 #node为保存当前节点 #当j与index相等时就 #相当于找到要删除的节点 j = 0 node = self.head prev = self.head while node._next and j < index: prev = node node = node._next j += 1 if j == index: prev._next = node._next self.length -= 1 修改一个节点: update() def update(self,index,data): if self.isEmpty() or index < 0 or index >= self.length: print 'error: out of index' return j = 0 node = self.head while node._next and j < index: node = node._next j += 1 if j == index: node.data = data 查找一个节点: getItem() def getItem(self,index): if self.isEmpty() or index < 0 or index >= self.length: print "error: out of index" return j = 0 node = self.head while node._next and j < index: node = node._next j += 1 return node.data 查找一个节点的索引: getIndex() def getIndex(self,data): j = 0 if self.isEmpty(): print "this chain table is empty" return node = self.head while node: if node.data == data: return j node = node._next j += 1 if j == self.length: print "%s not found" % str(data) return 插入一个节点: insert() def insert(self,dataOrNode): if self.isEmpty(): print "this chain tabale is empty" return if index < 0 or index >= self.length: print "error: out of index" return item = None if isinstance(dataOrNode,Node): item = dataOrNode else: item = Node(dataOrNode) if index == 0: item._next = self.head self.head = item self.length += 1 return j = 0 node = self.head prev = self.head while node._next and j < index: prev = node node = node._next j += 1 if j == index: item._next = node prev._next = item self.length += 1 清空链表: clear() def clear(self): self.head = None self.length = 0 以上就是链表类的要实现的方法。 执行的结果: 接下来是完整代码: # -*- coding:utf8 -*- #/usr/bin/env python class Node(object): def __init__(self,pnext = None): self.data = data self._next = pnext def __repr__(self): return str(self.data) class ChainTable(object): def __init__(self): self.head = None self.length = 0 def isEmpty(self): return (self.length == 0) def append(self,Node): item = dataOrNode else: item = Node(dataOrNode) if not self.head: self.head = item self.length += 1 else: node = self.head while node._next: node = node._next node._next = item self.length += 1 def delete(self,index): if self.isEmpty(): print "this chain table is empty." return if index < 0 or index >= self.length: print 'error: out of index' return if index == 0: self.head = self.head._next self.length -= 1 return j = 0 node = self.head prev = self.head while node._next and j < index: prev = node node = node._next j += 1 if j == index: prev._next = node._next self.length -= 1 def insert(self,dataOrNode): if self.isEmpty(): print "this chain tabale is empty" return if index < 0 or index >= self.length: print "error: out of index" return item = None if isinstance(dataOrNode,Node): item = dataOrNode else: item = Node(dataOrNode) if index == 0: item._next = self.head self.head = item self.length += 1 return j = 0 node = self.head prev = self.head while node._next and j < index: prev = node node = node._next j += 1 if j == index: item._next = node prev._next = item self.length += 1 def update(self,data): if self.isEmpty() or index < 0 or index >= self.length: print 'error: out of index' return j = 0 node = self.head while node._next and j < index: node = node._next j += 1 if j == index: node.data = data def getItem(self,index): if self.isEmpty() or index < 0 or index >= self.length: print "error: out of index" return j = 0 node = self.head while node._next and j < index: node = node._next j += 1 return node.data def getIndex(self,data): j = 0 if self.isEmpty(): print "this chain table is empty" return node = self.head while node: if node.data == data: return j node = node._next j += 1 if j == self.length: print "%s not found" % str(data) return def clear(self): self.head = None self.length = 0 def __repr__(self): if self.isEmpty(): return "empty chain table" node = self.head nlist = '' while node: nlist += str(node.data) + ' ' node = node._next return nlist def __getitem__(self,ind): if self.isEmpty() or ind < 0 or ind >= self.length: print "error: out of index" return return self.getItem(ind) def __setitem__(self,ind,val): if self.isEmpty() or ind < 0 or ind >= self.length: print "error: out of index" return self.update(ind,val) def __len__(self): return self.length 以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持编程小技巧。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |