python实现Floyd算法

# -*- coding: utf-8 -*- 
""" 
Created on Thu Jul 13 14:56:37 2017 
 
@author: linzr 
""" 
 
## 表示无穷大 
INF_val = 9999 
 
class Floyd_Path(): 
 def __init__(self,node,node_map,path_map): 
  self.node = node 
  self.node_map = node_map 
  self.node_length = len(node_map) 
  self.path_map = path_map 
  self._init_Floyd() 
  
 def __call__(self,from_node,to_node): 
  self.from_node = from_node 
  self.to_node = to_node 
  return self._format_path() 
 
 def _init_Floyd(self): 
  for k in range(self.node_length): 
   for i in range(self.node_length): 
    for j in range(self.node_length): 
     tmp = self.node_map[i][k] + self.node_map[k][j] 
     if self.node_map[i][j] > tmp: 
      self.node_map[i][j] = tmp 
      self.path_map[i][j] = self.path_map[i][k] 
       
  print '_init_Floyd is end' 
 
 
 def _format_path(self): 
  node_list = [] 
  temp_node = self.from_node 
  obj_node = self.to_node 
  print("the shortest path is: %d")%(self.node_map[temp_node][obj_node]) 
  node_list.append(self.node[temp_node]) 
  while True: 
   node_list.append(self.node[self.path_map[temp_node][obj_node]]) 
   temp_node = self.path_map[temp_node][obj_node] 
   if temp_node == obj_node: 
    break; 
   
  return node_list 
     
 
   
 
 
def set_node_map(node_map,node_list,path_map): 
 for i in range(len(node)): 
  ## 对角线为0 
  node_map[i][i] = 0 
 for x,y,val in node_list: 
  node_map[node.index(x)][node.index(y)] = node_map[node.index(y)][node.index(x)] = val 
  path_map[node.index(x)][node.index(y)] = node.index(y) 
  path_map[node.index(y)][node.index(x)] = node.index(x) 
 
  
if __name__ == "__main__": 
 node = ['A','B','C','D','E','F','G'] 
 node_list = [('A',9),('A',10),'G',15),('B',2),('G',3),12),('C',1),('E',7)] 
 
 ## node_map[i][j] 存储i到j的最短距离 
 node_map = [[INF_val for val in xrange(len(node))] for val in xrange(len(node))] 
 ## path_map[i][j]=j 表示i到j的最短路径是经过顶点j 
 path_map = [[0 for val in xrange(len(node))] for val in xrange(len(node))] 
  
 ## set node_map 
 set_node_map(node_map,path_map) 
 
 
 ## select one node to obj node,e.g. A --> D(node[0] --> node[3]) 
 from_node = node.index('A') 
 to_node = node.index('E') 
 Floydpath = Floyd_Path(node,path_map) 
 path = Floydpath(from_node,to_node) 
 print path