python – 从matplotlib的轮廓中获取坐标？

从the documentation example here开始,可以使用代码段轻松生成以下等高线图.

import matplotlib
import numpy as np
import matplotlib.cm as cm
import matplotlib.mlab as mlab
import matplotlib.pyplot as plt

matplotlib.rcParams['xtick.direction'] = 'out'
matplotlib.rcParams['ytick.direction'] = 'out'

delta = 0.025
x = np.arange(-3.0,3.0,delta)
y = np.arange(-2.0,2.0,delta)
X,Y = np.meshgrid(x,y)
Z1 = mlab.bivariate_normal(X,Y,1.0,0.0,0.0)
Z2 = mlab.bivariate_normal(X,1.5,0.5,1,1)
# difference of Gaussians
Z = 10.0 * (Z2 - Z1)

# Create a simple contour plot with labels using default colors.  The
# inline argument to clabel will control whether the labels are draw
# over the line segments of the contour,removing the lines beneath
# the label
plt.figure()
CS = plt.contour(X,Z)
plt.clabel(CS,inline=1,fontsize=10)
plt.title('Simplest default with labels')

我的目标

我已经获得了我的等高线图,同时得到了matplotlib.contour.QuadContourSet实例CS.在示例代码段中,CS仅用于clabel().但是对于我的情况,我需要获得轮廓线的方程或坐标集以进一步计算.

如何从实例CS中提取轮廓线的坐标？要么
我怎样才能以其他方式实现它？

我打赌必须有办法这样做.否则,轮廓事物只是一个“可视化的花瓶”.