Pythonic方法从字典中查找加权最小值和最大值的关键字
发布时间:2020-12-16 22:58:28 所属栏目:Python 来源:网络整理
导读:我正在使用与此类似的数据集: animals = { "antelope": { "latin": "Hippotragus equinus","cool_factor": 1,"popularity": 6 },"ostrich": { "latin": "Struthio camelus","cool_factor": 3,"popularity": 3 },"echidna": { "latin": "Tachyglossus aculea
我正在使用与此类似的数据集:
animals = { "antelope": { "latin": "Hippotragus equinus","cool_factor": 1,"popularity": 6 },"ostrich": { "latin": "Struthio camelus","cool_factor": 3,"popularity": 3 },"echidna": { "latin": "Tachyglossus aculeatus","cool_factor": 5,"popularity": 1 } } 我想要做的是找到受欢迎程度加权的“最不酷”和“最酷”的动物,这样: > min_cool_weighted(animals) "echidna" > max_cool_weighted(animals) "ostrich" 首先来到我的解决方案是创建3个数组(键,cool_factors和流行度),循环遍历字典,将所有值推入3个数组,然后创建第四个数组,每个值加权[i] = cool_factor [i] * popular [i],然后取最小值/最大值并从键阵列中获取相应的键.但是,这似乎不是Pythonic. 有更好,更有表现力的方式吗? 解决方法
max和
min就足够了
min(animals,key=lambda x: animals[x]["cool_factor"]*animals[x]["popularity"]) 'echidna' max(animals,key=lambda x: animals[x]["cool_factor"]*animals[x]["popularity"]) 'ostrich' (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |