python实现搜索指定目录下文件及文件内搜索指定关键词的方法
发布时间:2020-12-16 22:37:35 所属栏目:Python 来源:网络整理
导读:本篇章节讲解python实现搜索指定目录下文件及文件内搜索指定关键词的方法。供大家参考研究。具体实现方法如下: #!/usr/bin/python -O# -*- coding: UTF-8 -*-"""Sucht rekursiv in Dateiinhalten und listet die Fundstellen auf."""__author__ = "
本篇章节讲解python实现搜索指定目录下文件及文件内搜索指定关键词的方法。分享给大家供大家参考。具体实现方法如下: #!/usr/bin/python -O # -*- coding: UTF-8 -*- """ Sucht rekursiv in Dateiinhalten und listet die Fundstellen auf. """ __author__ = "Jens Diemer" __license__ = """GNU General Public License v2 or above - http://www.opensource.org/licenses/gpl-license.php""" __url__ = "http://www.jensdiemer.de" __version__ = "0.1" import os,time,fnmatch class search: def __init__(self,path,search_string,file_filter): self.search_path = path self.search_string = search_string self.file_filter = file_filter print "Search '%s' in [%s]..." % ( self.search_string,self.search_path ) print "_" * 80 time_begin = time.time() file_count = self.walk() print "_" * 80 print "%s files searched in %0.2fsec." % ( file_count,(time.time() - time_begin) ) def walk(self): file_count = 0 for root,dirlist,filelist in os.walk(self.search_path,followlinks=True): for filename in filelist: for file_filter in self.file_filter: if fnmatch.fnmatch(filename,file_filter): self.search_file(os.path.join(root,filename)) file_count += 1 return file_count def search_file(self,filepath): f = file(filepath,"r") content = f.read() f.close() if self.search_string in content: print filepath self.cutout_content(content) def cutout_content(self,content): current_pos = 0 search_string_len = len(self.search_string) for i in xrange(max_cutouts): try: pos = content.index(self.search_string,current_pos) except ValueError: break content_window = content[ pos - content_extract : pos + content_extract ] print ">>>",content_window.encode("String_Escape") current_pos += pos + search_string_len print if __name__ == "__main__": search_path = r"c:texte" file_filter = ("*.py",) # fnmatch-Filter search_string = "history" content_extract = 35 # Gr��e des Ausschnittes der angezeigt wird max_cutouts = 20 # Max. Anzahl an Treffer,die Angezeigt werden sollen search(search_path,file_filter) 希望本文所述对大家的Python程序设计有所帮助。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |