python selenium点击第n个元素
发布时间:2020-12-16 21:31:58 所属栏目:Python 来源:网络整理
导读:下面是检查代码,当鼠标位于图像上方时,基本上我想要点击图像…. ul id="product-list" li class="product one-col new" ul li class="image" title="sample image" a href="#product/1d77e790-f74a-3859-97db-c513cbece39c" img width="" height="" alt="" s
|
下面是检查代码,当鼠标位于图像上方时,基本上我想要点击图像….
<ul id="product-list">
<li class="product one-col new">
<ul>
<li class="image" title="sample image">
<a href="#product/1d77e790-f74a-3859-97db-c513cbece39c">
<img width="" height="" alt="" src="/content/images/1.jpg"></img>
<span class="new"> … </span>
<span class="hover"></span>
</a>
<p class="retailer"> … </p>
<p class="brand"></p>
</li>
<li class="price"> … </li>
<li class="name" title="sample image"> … </li>
<li class="first-seen"> … </li>
</ul>
</li>
<li class="product one-col new"> … </li>
<li class="product one-col new"> … </li>
<li class="product one-col new"> … </li>
我正在使用python selenium,并尝试了下面的单击span(悬停)链接 browser.find_element_by_css_selector("ul#product-list > :first-child > ul > li.image > a > span.hover ").click
但这不起作用……任何想法? 更新: browser.find_element_by_css_selector("ul#product-list > :first-child > ul > li.image > a > span.hover ").click()
File "/usr/lib/python2.7/site-packages/selenium-2.35.0-py2.7.egg/selenium/webdriver/remote/errorhandler.py",line 164,in check_response
raise exception_class(message,screen,stacktrace)
ElementNotVisibleException: Message: u'Element is not currently visible and so may not be interacted with' ; Stacktrace:
at fxdriver.preconditions.visible (file:///tmp/tmp6Pgi9F/extensions/fxdriver@googlecode.com/components/command_processor.js:8231)
at DelayedCommand.prototype.checkPreconditions_ (file:///tmp/tmp6Pgi9F/extensions/fxdriver@googlecode.com/components/command_processor.js:10823)
at DelayedCommand.prototype.executeInternal_/h (file:///tmp/tmp6Pgi9F/extensions/fxdriver@googlecode.com/components/command_processor.js:10840)
at DelayedCommand.prototype.executeInternal_ (file:///tmp/tmp6Pgi9F/extensions/fxdriver@googlecode.com/components/command_processor.js:10845)
at DelayedCommand.prototype.execute/< (file:///tmp/tmp6Pgi9F/extensions/fxdriver@googlecode.com/components/command_processor.js:10787)
更新: 这也行不通 browser.find_element_by_css_selector("ul#product-list > :first-child > ul > li.image > a ").click()
更新: 还尝试了动作链,鼠标点击..但没有运气.. element = browser.find_element_by_css_selector("ul#product-list > :first-child > ul > li.image")
hov = ActionChains(browser).move_to_element(element)
hov.click()
解决了: element_to_hover_over = driver.find_element_by_css_selector("ul#product-list > :first-child ")
hover = ActionChains(driver).move_to_element(element_to_hover_over)
hover.perform()
if "" == driver.find_element_by_css_selector("span.hover").text:
driver.find_element_by_css_selector("span.hover").click()
解决方法
你的代码缺失().如果没有(),则不会调用click方法.
browser.find_element_by_css_selector("ul...span.hover ").click()
# ^^
element = browser.find_element_by_css_selector("ul#product-list > :first-child > ul > li.image > a > span.hover ")
browser.execute_script("arguments[0].innerText = 'asdf';",element)
element.click()
(编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
