python selenium点击第n个元素
发布时间:2020-12-16 21:31:58 所属栏目:Python 来源:网络整理
导读:下面是检查代码,当鼠标位于图像上方时,基本上我想要点击图像…. ul id="product-list" li class="product one-col new" ul li class="image" title="sample image" a href="#product/1d77e790-f74a-3859-97db-c513cbece39c" img width="" height="" alt="" s
下面是检查代码,当鼠标位于图像上方时,基本上我想要点击图像….
<ul id="product-list"> <li class="product one-col new"> <ul> <li class="image" title="sample image"> <a href="#product/1d77e790-f74a-3859-97db-c513cbece39c"> <img width="" height="" alt="" src="/content/images/1.jpg"></img> <span class="new"> … </span> <span class="hover"></span> </a> <p class="retailer"> … </p> <p class="brand"></p> </li> <li class="price"> … </li> <li class="name" title="sample image"> … </li> <li class="first-seen"> … </li> </ul> </li> <li class="product one-col new"> … </li> <li class="product one-col new"> … </li> <li class="product one-col new"> … </li> 我正在使用python selenium,并尝试了下面的单击span(悬停)链接 browser.find_element_by_css_selector("ul#product-list > :first-child > ul > li.image > a > span.hover ").click 但这不起作用……任何想法? 更新: browser.find_element_by_css_selector("ul#product-list > :first-child > ul > li.image > a > span.hover ").click() File "/usr/lib/python2.7/site-packages/selenium-2.35.0-py2.7.egg/selenium/webdriver/remote/errorhandler.py",line 164,in check_response raise exception_class(message,screen,stacktrace) ElementNotVisibleException: Message: u'Element is not currently visible and so may not be interacted with' ; Stacktrace: at fxdriver.preconditions.visible (file:///tmp/tmp6Pgi9F/extensions/fxdriver@googlecode.com/components/command_processor.js:8231) at DelayedCommand.prototype.checkPreconditions_ (file:///tmp/tmp6Pgi9F/extensions/fxdriver@googlecode.com/components/command_processor.js:10823) at DelayedCommand.prototype.executeInternal_/h (file:///tmp/tmp6Pgi9F/extensions/fxdriver@googlecode.com/components/command_processor.js:10840) at DelayedCommand.prototype.executeInternal_ (file:///tmp/tmp6Pgi9F/extensions/fxdriver@googlecode.com/components/command_processor.js:10845) at DelayedCommand.prototype.execute/< (file:///tmp/tmp6Pgi9F/extensions/fxdriver@googlecode.com/components/command_processor.js:10787) 更新: 这也行不通 browser.find_element_by_css_selector("ul#product-list > :first-child > ul > li.image > a ").click() 更新: 还尝试了动作链,鼠标点击..但没有运气.. element = browser.find_element_by_css_selector("ul#product-list > :first-child > ul > li.image") hov = ActionChains(browser).move_to_element(element) hov.click() 解决了: element_to_hover_over = driver.find_element_by_css_selector("ul#product-list > :first-child ") hover = ActionChains(driver).move_to_element(element_to_hover_over) hover.perform() if "" == driver.find_element_by_css_selector("span.hover").text: driver.find_element_by_css_selector("span.hover").click() 解决方法
你的代码缺失().如果没有(),则不会调用click方法.
browser.find_element_by_css_selector("ul...span.hover ").click() # ^^ element = browser.find_element_by_css_selector("ul#product-list > :first-child > ul > li.image > a > span.hover ") browser.execute_script("arguments[0].innerText = 'asdf';",element) element.click() (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |