使用Jackson在Java中使用JSON序列化时遇到问题

我有一个JSON字符串,看起来像：

{
   "StatusCode":0,"Message":null,"ExecutionTime":0,"ResponseData":[
        {"Name":"name1","SiteId":"1234","Type":"Type1","X":"1234567","Y":"123456"},{"Name":"Name2","SiteId":"2134","Type":"Type2","Y":"1234567"},{"Name":"Name3","SiteId":"3241","Type":"Type3",{"Name":"Name4","SiteId":"4123","Type":"Type4","X":"123456","Y":"123456"}
    ]
}

我想创建一个可以检索X和Y值的对象.

我一直在尝试使用Jackson序列化JSON字符串,但没有成功.我为杰克逊创建了两个额外的课程.顶层的一个类,StatusCode,Message,ExecutionTime和ResponseData看起来像

public class PL {
private Long statusCode;
private String executionTime;
private String message;
private ResponseData responseData;
public PL(){
}

public void setStatusCode(Long statusCode){
  this.statusCode = statusCode;
}

public Long getStatusCode(){
  return this.statusCode;
}

public void setExecutionTime(String executionTime){
  this.executionTime = executionTime;
}
public String getExecutionTime(){
  return this.executionTime;
}

public void setMessage(String message){
  this.message = message;
}
public String getMessage(){
  return this.message;
}

public void setResponseData(ResponseData responseData){
  this.responseData = responseData;
}
public ResponseData getResponseData(){
  return this.responseData;
}
}

ReponseData作为对象返回的地方,然后我有另一个用于序列化ResponseData的类,看起来像

public class ResponseData {

private String name;
private String siteId;
private String type;
private String x;
private String y;

public ResponseData(){
}

public void setName(String name){
  this.name = name;
}
public String getName(){
  return this.name;
}

public void setSiteId(String siteId){
  this.siteId = siteId;
}
public String getSiteId(){
  return this.siteId;
}

public void setType(String type){
  this.type = type;
}
public String setType(){
  return this.type;
}

public void setX(String x){
  this.x = x;
}
public String getX(){
  return this.x;
}

public void setY(String y){
  this.y = y;
}
public String getY(){
  return this.y;
}
}

然后我创建一个ObjectMapper

private final static ObjectMapper mapper = new ObjectMapper();

并试着用这样读取值

ResponseData e = mapper.readValue(result.toString(),ResponseData.class);

并最终得到例外

com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field “StatusCode” (class MyClass.ResponseData),not marked as ignorable (5 known properties: “x”,“y”,“siteId”,“name”,“type”])

好像它无法解析第一个条目StatusMessage.即使我删除了第二个类,并且只尝试解析前面的四个条目,我将ResponseData作为String返回,我仍然得到相同的异常.