java – 同一个按钮多次单击

发布时间：2020-12-15 05:21:43 所属栏目：Java 来源：网络整理

导读：想法是按钮可以在第一次单击时执行一项操作,在第二次单击时执行不同的操作. button_food = (Button) findViewById(R.id.foodicon_layout);button_travel = (Button) findViewById(R.id.travelicon_layout);button_fuel = (Button) findViewById(R.id.fuelico

想法是按钮可以在第一次单击时执行一项操作,在第二次单击时执行不同的操作.

button_food   = (Button) findViewById(R.id.foodicon_layout);
button_travel = (Button) findViewById(R.id.travelicon_layout);
button_fuel   = (Button) findViewById(R.id.fuelicon_layout);
button_fetch  = (Button) findViewById(R.id.fetchicon_layout);

button_travel.setOnClickListener(new View.OnClickListener() {
    public void onClick(View v) {

        // Perform action on click
        button_food.setVisibility(View.GONE);
        button_fuel.setVisibility(View.GONE);
        button_fetch.setVisibility(View.GONE);
    }
});

在给定的示例中,单击button_travel时,其他按钮将变为不可见.再次点击相同我希望其他按钮再次可见.

解决方法

您可以通过获取当前可见性并切换它来使按钮设置其可见性.

button_food   = (Button) findViewById(R.id.foodicon_layout);
button_travel = (Button) findViewById(R.id.travelicon_layout);
button_fuel   = (Button) findViewById(R.id.fuelicon_layout);
button_fetch  = (Button) findViewById(R.id.fetchicon_layout);

button_travel.setOnClickListener(new View.OnClickListener() {
    public void onClick(View v) {

        int visibility = button_food.getVisibility() == View.VISIBLE ? View.GONE : View.VISIBLE;

        // Perform action on click
        button_food.setVisibility(visibility);
        button_fuel.setVisibility(visibility);
        button_fetch.setVisibility(visibility);
    }
});

像这样写它只是编写if语句的一种简单方法

int visibility;
if(button_food.getVisibility() == View.VISIBLE){
     visibility = View.GONE;
} else {
     visibility = View.VISIBLE;
}

（编辑：李大同）

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