java – 什么可以失败WifiP2pManager.connect？

该发现按预期工作,但当我尝试实际连接到所选设备时,系统调用ActionListener.onFailure并传递“内部错误”的原因代码.

这是启动连接的代码：

public void connectToDevice(WifiP2pDevice device) {
    Log.i(TAG,"Initiating connection to " + device.deviceAddress);
    stopScan();
    WifiP2pConfig config = new WifiP2pConfig();
    config.deviceAddress = device.deviceAddress;
    config.wps.setup = WpsInfo.PBC;
    // Since we wish to send a friend request,it will be easier if
    // we'll end up as a client because we will have the group owner's
    // address immediately.
    config.groupOwnerIntent = 0;
    mP2pManager.connect(mChannel,config,mConnectionListener);
}

mConnectionListener定义如下：

protected ActionListener mConnectionListener = new ActionListener() {
    @Override
    public void onSuccess() {
        Log.i(TAG,"Conection initiated successfuly");
    }

    @Override
    public void onFailure(int reason) {
        String reasonString = reason(reason);
        Log.e(TAG,"Error while connecting to Wifi peer: " + reasonString);
    }
};

抛出此错误时,设备不属于任何组,并且当任一设备(Nexus 4和Nexus 7)是启动器时会发生这种情况.

任何想法可能是什么问题？