java – Spring:url无法正确解析链接
虽然我对
Java很有经验,但我对Spring框架和Web应用程序都很陌生.当我在本地tomcat服务器上运行我的站点时,URL为:http:// localhost:8080 / myApp /
现在请求映射将我委托给我的主页: @RequestMapping(value = "/",method = RequestMethod.GET) public String someMethod(Model model) { ... return "index"; } 现在在index.xhtml文件中,我使用< a href =“apps /”> link< / a>链接到另一个页面 <spring:url value='/apps' var="apps_url" /> <a href="${apps_url}">link</a> 但是spring:url总是解析为http:// localhost:8080 / myApp / – 我目前所在的页面.另外,当我只使用这样的链接:< a href =“/ otherSite”> link< / a>时,它总是解析为http:// localhost:8080 / otherSite而不是http:// localhost: 8080 / myApp / otherSite就像我预期的那样.如何让我的链接工作?是http:// localhost:8080 / myApp隐式定义为我的上下文还是可以/应该更改为http:// localhost:8080 /? 此外,本地tomcat服务器上的URL与Web应用程序发布时的URL之间是否存在任何连接? 以下是我的一些应用程序文件: servlet的context.xml中: <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.1.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure --> <!-- Enables the Spring MVC @Controller programming model --> <annotation-driven /> <context:component-scan base-package="myApp" /> <tx:annotation-driven transaction-manager="transactionManager"/> <!-- Handles HTTP GET requests for /resources/** and /css/** by efficiently serving up static resources in the ${webappRoot}/resources directory --> <resources mapping="/resources/**" location="/resources/" /> <resources mapping="/css/**" location="/css/" /> <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <beans:property name="prefix" value="/WEB-INF/views/" /> <beans:property name="suffix" value=".xhtml" /> </beans:bean> </beans:beans> 摘自web.xml: <!-- The definition of the Root Spring Container shared by all Servlets and Filters --> <context-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/spring/root-context.xml</param-value> </context-param> <!-- Creates the Spring Container shared by all Servlets and Filters --> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <!-- Processes application requests --> <servlet> <servlet-name>appServlet</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>appServlet</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> 解决方法
最好将所有链接放在下面
<a href="${pageContext.servletContext.contextPath}/othersite"> Other site </a> ${pageContext.servletContext.contextPath}始终为您的应用程序提供root权限,当您开发使用http:// localhost:8080 / myApp时,您的应用程序root是/ myapp,但是当您希望将应用程序置于生产环境中时通常是您的应用程序root将是/,在链接之前使用${pageContext.servletContext.contextPath}确保它在两种情况下都能正常工作 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |