在java中无限循环
发布时间:2020-12-15 05:15:51 所属栏目:Java 来源:网络整理
导读:我是 Java新手.我试图从文本文件中提取员工数据并将其存储在集合中.我使用Stringtokenizer从文件中获取字符串,但在第二次迭代中,while循环变为无限;它不会出现在while循环中.我的代码是: public class Reader1 { String a; int i = 0; int count = 0; int x
我是
Java新手.我试图从文本文件中提取员工数据并将其存储在集合中.我使用Stringtokenizer从文件中获取字符串,但在第二次迭代中,while循环变为无限;它不会出现在while循环中.我的代码是:
public class Reader1 { String a; int i = 0; int count = 0; int x = 0; int y = 0; File f = new File( "C:Documents and SettingskmoorthiDesktopaksample.txt"); ArrayList<Employee> al = new ArrayList<Employee>(); public void notePad() throws IOException { try { FileReader fis = new FileReader(f); BufferedReader br = new BufferedReader(fis); do { a = br.readLine(); i++; if (i > 1) { if (a != null) { StringTokenizer st = new StringTokenizer(a," "); Employee e = new Employee(); System.out.println("hai1"); while (st.hasMoreTokens()) // here became infinite { count++; if (count == 1) { e.ename = st.nextToken(); al.add(e); } if (count == 2) { e.eno = st.nextToken(); al.add(e); } } } } } while (a != null); br.close(); } catch (FileNotFoundException q) { q.printStackTrace(); } } public void retrieve() { Iterator<Employee> it = al.iterator(); while (it.hasNext()) { Employee fi = (Employee) it.next(); String en = fi.ename; System.out.println(en); } } public static void main(String s[]) throws IOException { Reader1 r = new Reader1(); r.notePad(); r.retrieve(); } } 请提出解决方案. 解决方法
试试这个代码
while(st.hasMoreTokens()) { if(count==1) { e.ename=st.nextToken(); count++; } if(count==2) { e.eno=st.nextToken(); count=0; } a1.add(e); } 我想这会解决你的问题…. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |