java – Split String – 笛卡尔方式
发布时间:2020-12-15 05:15:36 所属栏目:Java 来源:网络整理
导读:给出以下字符串: “foo bar-baz-zzz” 我想将它分成字符“”和“ – ”,保留它们的值,但得到所有输入组合. 我想得到一个包含二维数组 {{"foo","bar","baz","zzz"},{"foo bar",{"foo","bar-baz",{"foo bar-baz","baz-zzz"},"bar-baz-zzz"},{"foo bar-baz-zzz
给出以下字符串:
“foo bar-baz-zzz” 我想将它分成字符“”和“ – ”,保留它们的值,但得到所有输入组合. 我想得到一个包含二维数组 {{"foo","bar","baz","zzz"},{"foo bar",{"foo","bar-baz",{"foo bar-baz","baz-zzz"},"bar-baz-zzz"},{"foo bar-baz-zzz"}} Java中是否有任何内置方法以这种方式拆分字符串?也许在像Apache Commons这样的库中?或者我必须写一个for循环的墙? 解决方法
这是一个有效的递归解决方案.我使用了List< List< String>>而不是二维数组,使事情更容易.代码有点难看,可能会整理一下.
样本输出: $java Main foo bar-baz-zzz Processing: foo bar-baz-zzz [foo,bar,baz,zzz] [foo,baz-zzz] [foo,bar-baz,bar-baz-zzz] [foo bar,zzz] [foo bar,baz-zzz] [foo bar-baz,zzz] [foo bar-baz-zzz] 码: import java.util.*; public class Main { public static void main(String[] args) { // First build a single string from the command line args. StringBuilder sb = new StringBuilder(); Iterator<String> it = Arrays.asList(args).iterator(); while (it.hasNext()) { sb.append(it.next()); if (it.hasNext()) { sb.append(' '); } } process(sb.toString()); } protected static void process(String str) { System.err.println("Processing: " + str); List<List<String>> results = new LinkedList<List<String>>(); // Invoke the recursive method that does the magic. process(str,results,new LinkedList<String>(),new StringBuilder()); for (List<String> result : results) { System.err.println(result); } } protected static void process(String str,int pos,List<List<String>> resultsSoFar,List<String> currentResult,StringBuilder sb) { if (pos == str.length()) { // Base case: Reached end of string so add buffer contents to current result // and add current result to resultsSoFar. currentResult.add(sb.toString()); resultsSoFar.add(currentResult); } else { // Step case: Inspect character at pos and then make recursive call. char c = str.charAt(pos); if (c == ' ' || c == '-') { // When we encounter a ' ' or '-' we recurse twice; once where we treat // the character as a delimiter and once where we treat it as a 'normal' // character. List<String> copy = new LinkedList<String>(currentResult); copy.add(sb.toString()); process(str,pos + 1,resultsSoFar,copy,new StringBuilder()); sb.append(c); process(str,currentResult,sb); } else { sb.append(c); process(str,sb); } } } } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |