Java int等式不一致?
发布时间:2020-12-15 05:06:50 所属栏目:Java 来源:网络整理
导读:这让我疯了,因为它完全违反了我去除它的努力: int k = keyCode; //keyCode being a variable declared by a keyPress//in the Processing library//k and keyCode are working properly.if ((k - UP)*500 == 0); //int UP=38;{ println((k-UP)*500 == 0); /
这让我疯了,因为它完全违反了我去除它的努力:
int k = keyCode; //keyCode being a variable declared by a keyPress //in the Processing library //k and keyCode are working properly. if ((k - UP)*500 == 0); //int UP=38; { println((k-UP)*500 == 0); //some other code here } 结果? “false”(并删除’== 0′,一个非0的数字). 有没有这样的不一致,可能是什么原因导致的? 解决方法
在if之后你有一个分号,所以总是执行println.
(编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |