Java说这个方法有一个构造函数名

但是由于某些原因,java不希望在构造函数之后拥有方法名称.

另外,当我试图将方法转换为另一种方法时,我使用isPalindrome时会出错.

我改变了我的程序,但我仍然遇到错误.

public class isPalindrome
{
    /**
     * This is the main entry point for the application
     * @return 
     */
    public static boolean main(String[] args) 
    {

    String[] word = {"KayaK","Desserts,I stressed"};



    boolean isPalindrome(String[] array,String s,String i)
    {

        if(i.charAt(0) == s.charAt(0))
        {
            System.out.println("You entered a Palindrome");
            return true;
        }
        else
        {
            System.out.println("You didn't entered a Palindrome");
        }
    }


        try 
        {
            System.in.read();
        } 
        catch (Throwable t) 
        {

        }
}

}