java – signature.verify()始终返回False

发布时间：2020-12-15 05:04:46 所属栏目：Java 来源：网络整理

导读：public static void main(String[] args) { try{ String mod = "q0AwozeUj0VVkoksDQSCTj3QEgODomq4sAr02xMyIrWldZrNHhWfZAIcWt2MuAY3X6S3ZVUfOFXOrVbltRrO3F9Z6R8/jJIMv7wjkeVBFC5gncwGR0C3aV9gmF6II19jTKfF1sxb26iMEMAlMEOSnAAceNaJH91zBoaW7ZIh+qk="; Stri

public static void main(String[] args) {
    try{
        String mod = "q0AwozeUj0VVkoksDQSCTj3QEgODomq4sAr02xMyIrWldZrNHhWfZAIcWt2MuAY3X6S3ZVUfOFXOrVbltRrO3F9Z6R8/jJIMv7wjkeVBFC5gncwGR0C3aV9gmF6II19jTKfF1sxb26iMEMAlMEOSnAAceNaJH91zBoaW7ZIh+qk=";
        String exp = "AQAB";
        byte[] modulusBytes = Base64.decodeBase64(mod.getBytes("UTF-8"));
        byte[] exponentBytes = Base64.decodeBase64(exp.getBytes("UTF-8"));
        String signedMessage = "3753e672cfb21e3c182ef2df51f19edeffb63432ed338a47251326ccc14aa63883e910a140cf313754ebc6425aad434e309307cc882da6cd4a4f9f40bd14a9823aca145e5ffc97cd63dbb5925c049282416bdfd7d74ddeef7055065210a841793fe315dff5a44af19c1522daafdc2f7e61ce5a2b42ebf79dfb086e6d210168dd";
        BigInteger modulus = new BigInteger(1,modulusBytes );               
        BigInteger exponent = new BigInteger(1,exponentBytes);
        RSAPublicKeySpec rsaPubKey = new RSAPublicKeySpec(modulus,exponent);
        KeyFactory fact = KeyFactory.getInstance("RSA");
        PublicKey pubKey = fact.generatePublic(rsaPubKey);
        Signature signature = Signature.getInstance("SHA1withRSA");
        byte[] sigBytes = hexStringToByteArray(signedMessage);
        signature.initVerify(pubKey);
        System.out.println(signature.verify(sigBytes));
    }catch(Exception e){
        System.out.println("Error: " + e.toString());
    }
}
private static byte[] hexStringToByteArray(final String encoded) {
    if ((encoded.length() % 2) != 0)
        throw new IllegalArgumentException("Input string must contain an even number of characters");

    final byte result[] = new byte[encoded.length()/2];
    final char enc[] = encoded.toCharArray();
    for (int i = 0; i < enc.length; i += 2) {
        StringBuilder curr = new StringBuilder(2);
        curr.append(enc[i]).append(enc[i + 1]);
        result[i/2] = (byte) Integer.parseInt(curr.toString(),16);
    }
    return result;
}

此代码始终返回false.我不知道从哪里开始.

解决方法

在您对邮件进行签名的地方,您应该拥有以下代码：

Signature signature = Signature.getInstance("SHA1withRSA");
signature.initSign(privKey);
signature.update(message);
byte[] signatureValue = signature.sign();

请注意名为signatureValue的字节数组.这是数据的实际签名.这就是你应该提供给verify() – 方法的东西.应该在调用update() – 方法时提供已签名的消息.即：

Signature signature = Signature.getInstance("SHA1withRSA");
signature.initVerify(pubKey);
signature.update(message);
bool ok = signature.verify(signatureValue);

（编辑：李大同）

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