java – 如何在继续之前等待所有callables完成执行?
发布时间:2020-12-15 05:00:41 所属栏目:Java 来源:网络整理
导读:我有以下代码哈希: public class MyCallable implements CallableLong { @Override public Long call() throws Exception { // Do stuff... }}public class MyController { private ExecutorService executor = Executos.newCachedTreadPool(); public Long
我有以下代码哈希:
public class MyCallable implements Callable<Long> { @Override public Long call() throws Exception { // Do stuff... } } public class MyController { private ExecutorService executor = Executos.newCachedTreadPool(); public Long concurrentDoStuff() { List<MyCallable> workers = makeWorkers(); List<Long> allResults = new ArrayList<Long>(); for(MyCallable worker : workers) { Future<Long> workerResults = executor.submit(worker); try { allResults.add(workerResults.get()); } catch(InterruptedException ie) { // Handle... } catch(ExecutionException ee) { // Handle... } } // Question: how do I pause here and wait for all workers to finish? } } 在for循环之后,我想等待所有工人完成任务以继续进行.什么是最好/最安全/最有效的方法?提前致谢! 解决方法
您必须使用shutDown关闭Executor,然后等待所有作业都使用awaitTermination进行处理.
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