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如何通过从java流中的子对象过滤来检索父对象

发布时间:2020-12-15 04:40:39 所属栏目:Java 来源:网络整理
导读:人是我的根POJA,我有作为我的孩子对象的电话号码列表. String firstName;String lastName;Long id;ListString phoneNumber = new ArrayList();int age;public Person(String firstName,String lastName,int age,Long id,ListString phone) { super(); this.f
人是我的根POJA,我有作为我的孩子对象的电话号码列表.

String firstName;

String lastName;

Long id;

List<String> phoneNumber = new ArrayList<>();

int age;


public Person(String firstName,String lastName,int age,Long id,List<String> phone) {
    super();
    this.firstName = firstName;
    this.lastName = lastName;
    this.age = age;
    this.id = id;
    this.phoneNumber = phone;
}

List<Person> personList = Arrays.asList(
    new Person("Abdul","Razak",27,50L,Arrays.asList("100","101","102")),new Person("Udemy","tut",56,60L,Arrays.asList("200","201","202")),new Person("Coursera",78,20L,Arrays.asList("300","301","302")),new Person("linked",14,10L,Arrays.asList("400","401","402")),new Person("facebook",24,5L,Arrays.asList("500","501","502")),new Person("covila",34,22L,Arrays.asList("600","602","604")),new Person("twitter",64,32L,Arrays.asList("700","702","704"))
);

List<String> list = personList.stream()
    .map(p -> p.getPhoneNumber().stream())
    .flatMap(inputStream -> inputStream)
    .filter(p -> p.contains("502"))
    .collect(Collectors.toList());

我想检索其数字等于特定字符串的人.是否可以通过使用流来实现这一点?

List<String> list = personList.stream()
    .map(p -> p.getPhoneNumber().stream())
    .flatMap(inputStream -> inputStream)
    .filter(p -> p.contains("502"))
    .collect(Collectors.toList());

简单来说,如何通过过滤子对象来检索父对象?

解决方法

personList.stream().filter((person)->person.getContacts().contains("100"))
                .collect(Collectors.toList());

会给你匹配的人.

(编辑:李大同)

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